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Int32 means you have 32 bits available to store your number. The highest bit is the sign-bit, this indicates if the number is positive or negative. So you have 2^31 bits for positive and negative numbers. With zero being a positive number you get the logical range of (mentioned before) +2147483647 to -2147483648. If you think that is to small ...
First off, neither IEEE-754-2008 nor -1985 have 16-bit floats; but it is a proposed addition with a 5-bit exponent and 10-bit fraction. IEE-754 uses a dedicated sign bit, so the positive and negative range is the same. Also, the fraction has an implied 1 in front, so you get an extra bit.
Two raised to the power of thirty-two is just the same, just a bit set to one in the 32nd position, which is the most significant bit of a 32-bit number: 10000000 00000000 00000000 00000000 If this 32-bit number we are talking about is unsigned, then the number in question represents the value of 4,294,967,296, so around 4 billion, the max ...
The most common 32-bit floating-point format, IEEE-754 binary32, does not have eight bits for the whole number part. It has one bit for a sign, eight bits for an exponent field, and 23 bits for a significand field (a fraction part). The sign bit determines whether the number is positive (0) or negative (1). The exponent field, e, has several uses.
It has minimum -32768 and maximum +32767 value. Int32. It is a FCL type. In C#, int is mapped to Int32. It is a value type and represent System.Int32 struct. It is signed and takes 32 bits. It has minimum -2147483648 and maximum +2147483647 value. Int64.
25. I saw in MSDN documents that the maximum value of Int32 is 2,147,483,647, hexadecimal 0x7FFFFFFF. I think, if it's Int32 it should store 32-bit integer values that finally should be 4,294,967,295 and hexadecimal 0xFFFFFFFF.
Signed integers are not nearly as complex - you still have 2^32 bit patterns, and again 2^32 different values. All values differ by exactly one, so the difference between the min and the max value has to be 2^32-1. For obvious reasons, the range is chosen centered around 0, so you have roughly 2^32/2 = 2^31 values lower than 0 and 2^31 values ...
This is the maximum number of VALUES that a binary number with 32 digits (a 32-bit number) can represent. Those values can be any values in any range. In an UNSIGNED 32-bit number, the valid values are from 0 to 2³² − 1 (instead of 1 to 2³², but the same number of VALUES, about 4.2 billion). In a SIGNED 32-bit number, one of the 32 bits ...
However, there's IEEE754 format for decimal floating point, which encodes numbers somewhat differently, and uses either Binary Integer Decimal (BID) or Densely Packed Decimal (DPD) for binary encoding of decimal numbers. Regardless of the encoding, decimal can store 7 decimal digits in coefficient and values [-95, 96] in the exponent, if the ...
In your case, if the number of bits on IEEE 754 are: 16 Bits you have 1 for the sign, 5 for the exponent and 10 for the mantissa. The largest number represented is 4,293,918,720. 32 Bits you have 1 for the sign, 8 for the exponent and 23 for the mantissa. The largest number represented is 3.402823466E38.