Search results
Results from the WOW.Com Content Network
This sequence of approximations begins 1 / 1 , 3 / 2 , 7 / 5 , 17 / 12 , and 41 / 29 , so the sequence of Pell numbers begins with 1, 2, 5, 12, and 29. The numerators of the same sequence of approximations are half the companion Pell numbers or Pell–Lucas numbers ; these numbers form a second infinite ...
Name First elements Short description OEIS Kolakoski sequence: 1, 2, 2, 1, 1, 2, 1, 2, 2, 1, ... The n th term describes the length of the n th run : A000002: Euler's ...
That 641 is a factor of F 5 can be deduced from the equalities 641 = 2 7 × 5 + 1 and 641 = 2 4 + 5 4. It follows from the first equality that 2 7 × 5 ≡ −1 (mod 641) and therefore (raising to the fourth power) that 2 28 × 5 4 ≡ 1 (mod 641).
Up Next: - 15 Fun Games Like Connections to Play Every Day - Hints, Clues and Answers to the NYT's 'Mini Crossword' Puzzle. Related: Today’s NYT ‘Strands’ Hints, Spangram and Answers for ...
The average Los Angeles home is worth about $948,000, according to Zillow.But a lot of homes in the area are worth considerably more. So if you have a $1.5 million property, you're not necessarily ...
With the exceptions of 1, 8 and 144 (F 1 = F 2, F 6 and F 12) every Fibonacci number has a prime factor that is not a factor of any smaller Fibonacci number (Carmichael's theorem). [56] As a result, 8 and 144 ( F 6 and F 12 ) are the only Fibonacci numbers that are the product of other Fibonacci numbers.
The (−2, 3, 7) pretzel knot has 7 exceptional slopes, Dehn surgery slopes which give non-hyperbolic 3-manifolds. Among the enumerated knots, the only other hyperbolic knot with 7 or more is the figure-eight knot, which has 10. All other hyperbolic knots are conjectured to have at most 6 exceptional slopes. A pretzel (−2,3,7) pretzel knot.
Related: Our List of 205 'Paranoia Questions' Will Be Perfect for Your Next Game Night. ... 5. Rapper and a flapper 6. Gumball machine and Dairy Queen 7. Snowflake and a birthday cake 8. Chimney ...