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The quadratic equation on a number can be solved using the well-known quadratic formula, which can be derived by completing the square. That formula always gives the roots of the quadratic equation, but the solutions are expressed in a form that often involves a quadratic irrational number, which is an algebraic fraction that can be evaluated ...
A similar but more complicated method works for cubic equations, which have three resolvents and a quadratic equation (the "resolving polynomial") relating and , which one can solve by the quadratic equation, and similarly for a quartic equation (degree 4), whose resolving polynomial is a cubic, which can in turn be solved. [14]
[4] [5] Because the quadratic equation involves only one unknown, it is called "univariate". The quadratic equation contains only powers of x that are non-negative integers, and therefore it is a polynomial equation. In particular, it is a second-degree polynomial equation, since the greatest power is two.
Bernoulli's equation; Bogoliubov–Born–Green–Kirkwood–Yvon hierarchy of equations; Bessel's differential equation; Boltzmann equation; Borda–Carnot equation; Burgers' equation; Darcy–Weisbach equation; Dirac equation. Dirac equation in the algebra of physical space; Dirac–Kähler equation; Doppler equations; Drake equation (aka ...
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Given a quadratic polynomial of the form + the numbers h and k may be interpreted as the Cartesian coordinates of the vertex (or stationary point) of the parabola. That is, h is the x -coordinate of the axis of symmetry (i.e. the axis of symmetry has equation x = h ), and k is the minimum value (or maximum value, if a < 0) of the quadratic ...
2) Quadratic Functions 2.1 Quadratic Equations and Inequalities; 2.2 Types of Roots of Quadratic Equations; 2.3 Quadratic Functions; 3) Systems of Equations 3.1 Systems of Linear Equations in Three Variables; 3.2 Simultaneous Equations involving One Linear Equation and One Non-Linear Equations; 4) Indices, Surds and Logarithms 4.1 Law of Indices
One root of this equation is z 0 = 1 which corresponds to the point P 0 (1, 0). Removing the factor corresponding to this root, the other roots turn out to be roots of the equation z 4 + z 3 + z 2 + z + 1 = 0. These roots can be represented in the form ω, ω 2, ω 3, ω 4 where ω = exp (2i π /5). Let these correspond to the points P 1, P 2 ...
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