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{{Convert}} uses unit-codes, which are similar to, but not necessarily exactly the same as, the usual written abbreviation for a given unit. These unit-codes are displayed in column 3 of the following tables. These are accepted as input by {{convert}} as the second and third unnamed parameters: {{convert|100|kg|lb}} → 100 kilograms (220 lb)
Converts measurements to other units. Template parameters [Edit template data] This template prefers inline formatting of parameters. Parameter Description Type Status Value 1 The value to convert. Number required From unit 2 The unit for the provided value. Suggested values km2 m2 cm2 mm2 ha sqmi acre sqyd sqft sqin km m cm mm mi yd ft in kg g mg lb oz m/s km/h mph K C F m3 cm3 mm3 L mL cuft ...
Units should be discussed at Template talk:Convert. This page is read by a script ( makeunits ). The script extracts information from the wikitext, and outputs the Lua source that defines the table of units; that source can be manually copied into Module:Convert/data .
Mass flow rate is defined by the limit [3] [4] ˙ = =, i.e., the flow of mass through a surface per time .. The overdot on ˙ is Newton's notation for a time derivative.Since mass is a scalar quantity, the mass flow rate (the time derivative of mass) is also a scalar quantity.
The newton (symbol: N) is the unit of force in the International System of Units (SI). Expressed in terms of SI base units, it is 1 kg⋅m/s 2, the force that accelerates a mass of one kilogram at one metre per second squared. The unit is named after Isaac Newton in recognition of his work on classical mechanics, specifically his second law of ...
In engineering and physics, g c is a unit conversion factor used to convert mass to force or vice versa. [1] It is defined as = In unit systems where force is a derived unit, like in SI units, g c is equal to 1.
Mathematically, mass flux is defined as the limit =, where = = is the mass current (flow of mass m per unit time t) and A is the area through which the mass flows.. For mass flux as a vector j m, the surface integral of it over a surface S, followed by an integral over the time duration t 1 to t 2, gives the total amount of mass flowing through the surface in that time (t 2 − t 1): = ^.
newton dyne kilogram-force, kilopond pound-force poundal; 1 N : ≡ 1 kg⋅m/s 2 = 10 5 dyn ≈ 0.101 97 kp: ≈ 0.224 81 lb F: ≈ 7.2330 pdl: 1 dyn = 10 −5 N ≡ 1 g⋅cm/s 2