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54 as the sum of three positive squares. 54 is an abundant number [1] because the sum of its proper divisors , [2] which excludes 54 as a divisor, is greater than itself. Like all multiples of 6, [3] 54 is equal to some of its proper divisors summed together, [a] so it is also a semiperfect number. [4]
Download as PDF; Printable version; In other projects ... ≡ 2.54 cm ≡ 1 ⁄ 36 yd ≡ 1 ... 1 ⁄ 100 of the energy required to warm one gram of air-free water ...
Two numbers with the same "abundancy" form a friendly pair; n numbers with the same abundancy form a friendly n-tuple. Being mutually friendly is an equivalence relation, and thus induces a partition of the positive naturals into clubs (equivalence classes) of mutually friendly numbers. A number that is not part of any friendly pair is called ...
m is a divisor of n (also called m divides n, or n is divisible by m) if all prime factors of m have at least the same multiplicity in n. The divisors of n are all products of some or all prime factors of n (including the empty product 1 of no prime factors). The number of divisors can be computed by increasing all multiplicities by 1 and then ...
However, amicable numbers where the two members have different smallest prime factors do exist: there are seven such pairs known. [8] Also, every known pair shares at least one common prime factor. It is not known whether a pair of coprime amicable numbers exists, though if any does, the product of the two must be greater than 10 65.
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In mathematics, a product is the result of multiplication, or an expression that identifies objects (numbers or variables) to be multiplied, called factors. For example, 21 is the product of 3 and 7 (the result of multiplication), and x ⋅ ( 2 + x ) {\displaystyle x\cdot (2+x)} is the product of x {\displaystyle x} and ( 2 + x ) {\displaystyle ...
The factorizations are often not unique in the sense that the unit could be absorbed into any other factor with exponent equal to one. The entry 4+2i = −i(1+i) 2 (2+i), for example, could also be written as 4+2i= (1+i) 2 (1−2i). The entries in the table resolve this ambiguity by the following convention: the factors are primes in the right ...