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Trajectory of a particle with initial position vector r 0 and velocity v 0, subject to constant acceleration a, all three quantities in any direction, and the position r(t) and velocity v(t) after time t. The initial position, initial velocity, and acceleration vectors need not be collinear, and the equations of motion take an almost identical ...
The general formula for the escape velocity of an object at a distance r from the center of a planet with mass M is [12] = =, where G is the gravitational ...
This is the equation of a parabola, so the path is parabolic. The axis of the parabola is vertical. If the projectile's position (x,y) and launch angle (θ or α) are known, the initial velocity can be found solving for v 0 in the afore-mentioned parabolic equation:
A rocket's required mass ratio as a function of effective exhaust velocity ratio. The classical rocket equation, or ideal rocket equation is a mathematical equation that describes the motion of vehicles that follow the basic principle of a rocket: a device that can apply acceleration to itself using thrust by expelling part of its mass with high velocity and can thereby move due to the ...
The initial velocity, v i, is the speed at which said object is launched from the point of origin. The initial angle , θ i , is the angle at which said object is released. The g is the respective gravitational pull on the object within a null-medium.
In the solution, c 1 and c 2 are two constants determined by the initial conditions (specifically, the initial position at time t = 0 is c 1, while the initial velocity is c 2 ω), and the origin is set to be the equilibrium position.
v 1 (v A1 or v B1) is the initial velocity of the particle. If both masses are the same, we have a trivial solution: = =. This simply corresponds to the bodies exchanging their initial velocities with each other. [2]
The velocity equation for a hyperbolic trajectory is = ... the satellite's initial position and velocity vectors and at a given epoch =. In a two-body simulation ...