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Cameron–Erdős conjecture: sum-free sets: 2003: Nils Dencker: Nirenberg–Treves conjecture: pseudo-differential operators: 2004 (see comment) Nobuo Iiyori and Hiroshi Yamaki: Frobenius conjecture: group theory: A consequence of the classification of finite simple groups, completed in 2004 by the usual standards of pure mathematics. 2004 ...
The Collatz conjecture [a] is one of the most famous unsolved problems in mathematics. The conjecture asks whether repeating two simple arithmetic operations will eventually transform every positive integer into 1.
A conjecture with Norman Oler [2] on circle packing in an equilateral triangle with a number of circles one less than a triangular number. The minimum overlap problem to estimate the limit of M(n). A conjecture that the ternary expansion of contains at least one digit 2 for every >. [3]
The Clay Institute has pledged a US $1 million prize for the first correct solution to each problem. The Clay Mathematics Institute officially designated the title Millennium Problem for the seven unsolved mathematical problems, the Birch and Swinnerton-Dyer conjecture, Hodge conjecture, Navier–Stokes existence and smoothness, P versus NP ...
In mathematics, the Birch and Swinnerton-Dyer conjecture (often called the Birch–Swinnerton-Dyer conjecture) describes the set of rational solutions to equations defining an elliptic curve. It is an open problem in the field of number theory and is widely recognized as one of the most challenging mathematical problems.
Goldbach’s Conjecture. One of the greatest unsolved mysteries in math is also very easy to write. Goldbach’s Conjecture is, “Every even number (greater than two) is the sum of two primes ...
Download QR code; Print/export ... In mathematics, Fujita's conjecture is a problem in the theories of algebraic geometry ... "On Fujita's conjecture", Duke ...
The Fermat–Catalan conjecture is an open conjecture dealing with such cases (the condition of this conjecture is that the sum of the reciprocals is less than 1). If we allow at most one of the exponents to be 2, then there may be only finitely many solutions (except the case 1 m + 2 3 = 3 2 {\displaystyle 1^{m}+2^{3}=3^{2}} ).