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  2. There are different ways you can achieve if-then-else. Using when function in DataFrame API. You can specify the list of conditions in when and also can specify otherwise what value you need.

  3. To make it more generic of keeping both columns in df1 and df2:. import pyspark.sql.functions as F # Keep all columns in either df1 or df2 def outter_union(df1, df2): # Add missing columns to df1 left_df = df1 for column in set(df2.columns) - set(df1.columns): left_df = left_df.withColumn(column, F.lit(None)) # Add missing columns to df2 right_df = df2 for column in set(df1.columns) - set(df2 ...

  4. Pyspark: Filter dataframe based on multiple conditions

    stackoverflow.com/questions/49301373

    79. I want to filter dataframe according to the following conditions firstly (d<5) and secondly (value of col2 not equal its counterpart in col4 if value in col1 equal its counterpart in col3). If the original dataframe DF is as follows: The desired Dataframe is: Code I have tried that did not work as expected:

  5. Pyspark: Convert column to lowercase - Stack Overflow

    stackoverflow.com/questions/47179745

    import pyspark.sql.functions as F df.select("*", F.lower("my_col")) this returns a data frame with all the original columns, plus lowercasing the column which needs it. Share

  6. When using PySpark, it's often useful to think "Column Expression" when you read "Column". Logical operations on PySpark columns use the bitwise operators: & for and. | for or. ~ for not. When combining these with comparison operators such as <, parenthesis are often needed. In your case, the correct statement is:

  7. The selected correct answer does not address the question, and the other answers are all wrong for pyspark. There is no "!=" operator equivalent in pyspark for this solution. The correct answer is to use "==" and the "~" negation operator, like this:

  8. import pyspark.sql.functions as F import pyspark.sql as SQL win = SQL.Window.partitionBy('column_of_values') Then all you need it to use count aggregation partitioned by the window: df.select(F.count('column_of_values').over(win).alias('histogram'))

  9. cannot resolve column due to data type mismatch PySpark

    stackoverflow.com/questions/60646254

    As you are accessing array of structs we need to give which element from array we need to access i.e 0,1,2..etc.

  10. You should add, in your answer, the lines from functools import reduce from pyspark.sql import DataFrame So people don't have to look further up. – Laurent Commented Dec 2, 2021 at 13:09

  11. Python Spark Cumulative Sum by Group Using DataFrame

    stackoverflow.com/questions/45946349

    This can be done using a combination of a window function and the Window.unboundedPreceding value in the window's range as follows: from pyspark.sql import Window. from pyspark.sql import functions as F. windowval = (Window.partitionBy('class').orderBy('time') .rangeBetween(Window.unboundedPreceding, 0))