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1) The function DATEDIFF () is responsible to calculate differences between two dates, the result could be " year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond ", specified on the first parameter (datepart): select datediff(day,'1997-10-07','2011-09-11') 2) You can use the function GETDATE () to get the ...
All datediff() does is compute the number of period boundaries crossed between two dates. For instance. datediff(yy,'31 Dec 2013','1 Jan 2014')
DATEDIFF(hour, start_date, end_date) will give you the number of hour boundaries crossed between start_date and end_date. If you need the number of fractional hours, you can use DATEDIFF at a higher resolution and divide the result: DATEDIFF(second, start_date, end_date) / 3600.0 The documentation for DATEDIFF is available on MSDN:
SELECT '-12') [months] ORDER BY 1. Then, convert your Time1 and Time2 date points into the 'yyyy-mm' format (Think of these as the coordinate cut points on the whole cloth). Retain the original datetime versions of the points as well: SELECT. Time1 = @Time1, [YYYY-MM of Time1] = CASE.
For workdays, Monday to Friday, you can do it with a single SELECT, like this: DECLARE @StartDate DATETIME DECLARE @EndDate DATETIME SET @StartDate = '2008/10/01' SET @EndDate = '2008/10/31' SELECT (DATEDIFF(dd, @StartDate, @EndDate) + 1) -(DATEDIFF(wk, @StartDate, @EndDate) * 2) -(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END) -(CASE WHEN DATENAME(dw, @EndDate) = 'Saturday ...
SQL Supports datetime substraction which outputs a new datetime relative to the MIN date (for instance 1900-01-01, you can probably get this value from some system variable) This works better than DATEDIFF, because DATEDIFF will count ONE for each "datepart boundaries crossed", even if the elapsed time is less than a whole datapart.
Microsoft's ISNULL () function is used to specify how we want to treat NULL values. In this case we want NULL values to be zero. Below, if "UnitsOnOrder" is NULL it will not harm the calculation, because ISNULL () returns a zero if the value is NULL: SQL Server / MS Access. SELECT ProductName,UnitPrice*(UnitsInStock+ISNULL(UnitsOnOrder,0)) FROM ...
6. You can simply subtract two dates. You have to cast it first, using to_date: - to_date('2000-01-02', 'yyyy-MM-dd') datediff. The result is in days, to the difference of these two dates is -1 (you could swap the two dates if you like). If you like to have it in hours, just multiply the result with 24.
96. Your calculation is correct for DATE types, but if your values are timestamps, you should probably use EXTRACT (or DATE_PART) to be sure to get only the difference in full days; EXTRACT(DAY FROM MAX(joindate)-MIN(joindate)) AS DateDifference. An SQLfiddle to test with. Note the timestamp difference being 1 second less than 2 full days.
6. Create this function, it will give exact date difference like year months days. Create function get_Exact_Date_diff(@date smalldatetime,@date2 smalldatetime) returns varchar(50) as. begin. declare @date3 smalldatetime. Declare @month int,@year int,@day int. if @date>@date2.