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C-value is the amount, in picograms, of DNA contained within a haploid nucleus (e.g. a gamete) or one half the amount in a diploid somatic cell of a eukaryotic organism. In some cases (notably among diploid organisms), the terms C-value and genome size are used interchangeably; however, in polyploids the C-value may represent two or more genomes contained within the same nucleus.
1 Table of physical constants. 2 Uncertainties. ... [c] 1.088(30) × 10 −52 m −2 ... (its value is exactly 1 Da), ...
The maximum value of N is provided by BITINT_MAXWIDTH and is at least ULLONG_WIDTH. Therefore, the type _BitInt (2) (or signed _BitInt (2)) takes values from −2 to 1 while unsigned _BitInt (2) takes values from 0 to 3. The type unsigned _BitInt (1) also exists, being either 0 or 1 and has no equivalent signed type. [13]
To find a negative value such as –0.83, one could use a cumulative table for negative z-values [3] which yield a probability of 0.20327. But since the normal distribution curve is symmetrical, probabilities for only positive values of Z are typically given.
The specific heat of a slave is calculated from the measured values of individual tissues is 2.98 kJ · kg−1 · °C−1. This is 17% lower than the earlier wider used one based on non measured values of 3.47 kJ · kg−1· °C−1.
Despite that, the radix has historically been binary (base 2), meaning numbers like 1/2 or 1/4 are exact, but not 1/10, 1/100 or 1/3. With decimal floating point all the same numbers are exact plus numbers like 1/10 and 1/100, but still not e.g. 1/3. No known implementation does opt into the decimal radix for the previously known to be binary ...
0110 (decimal 6) AND 1011 (decimal 11) = 0010 (decimal 2) Because of this property, it becomes easy to check the parity of a binary number by checking the value of the lowest valued bit. Using the example above: 0110 (decimal 6) AND 0001 (decimal 1) = 0000 (decimal 0) Because 6 AND 1 is zero, 6 is divisible by two and therefore even.
The most significant bit of the first number is 1 and that of the second number is also 1 so the most significant bit of the result is 1; in the second most significant bit, the bit of second number is zero, so we have the result as 0. [2]