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The equilateral cylinder is characterized by being a right circular cylinder in which the diameter of the base is equal to the value of the height (geratrix). [ 4 ] Then, assuming that the radius of the base of an equilateral cylinder is r {\displaystyle r\,} then the diameter of the base of this cylinder is 2 r {\displaystyle 2r\,} and its ...
For a given volume, the right circular cylinder with the smallest surface area has h = 2r. Equivalently, for a given surface area, the right circular cylinder with the largest volume has h = 2r, that is, the cylinder fits snugly in a cube of side length = altitude ( = diameter of base circle). [8]
The ratio of the volume of a sphere to the volume of its circumscribed cylinder is 2:3, as was determined by Archimedes. The principal formulae derived in On the Sphere and Cylinder are those mentioned above: the surface area of the sphere, the volume of the contained ball, and surface area and volume of the cylinder.
Within the cylinder is the cone whose apex is at the center of one base of the cylinder and whose base is the other base of the cylinder. By the Pythagorean theorem , the plane located y {\displaystyle y} units above the "equator" intersects the sphere in a circle of radius r 2 − y 2 {\textstyle {\sqrt {r^{2}-y^{2}}}} and area π ( r 2 − y ...
Volume Cuboid: a, b = the sides of the cuboid's base c = the third side of the cuboid Right-rectangular ... Right circular cylinder: r = the radius of the cylinder
When applying prefixes to units of volume, which are expressed in units of length cubed, the cube operators are applied to the unit of length including the prefix. An example of converting cubic centimetre to cubic metre is: 2.3 cm 3 = 2.3 (cm) 3 = 2.3 (0.01 m) 3 = 0.0000023 m 3 (five zeros). [18]: 143
1.49 × 10 2: Volume of any A Division New York City Subway car: 1 × 10 ^ 3 m 3 (35,000 cu ft; 1.0 × 10 −6 km 3) One cubic decametre or one megalitre: 1.233 × 10 3: One acre-foot: 2.5 × 10 3: Volume of an Olympic size swimming pool of minimal depth (50 m × 25 m × 2 m). 3.054 × 10 3: Volume of each of the nine spheres of the Atomium in ...
The problem of potential compressible flow over circular cylinder was first studied by O. Janzen in 1913 [4] and by Lord Rayleigh in 1916 [5] with small compressibility effects. Here, the small parameter is the square of the Mach number M 2 = U 2 / c 2 ≪ 1 {\displaystyle \mathrm {M} ^{2}=U^{2}/c^{2}\ll 1} , where c is the speed of sound .