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4-Aminophenol (or para-aminophenol or p-aminophenol) is an organic compound with the formula H 2 NC 6 H 4 OH. Typically available as a white powder, [ 3 ] it is commonly used as a developer for black-and-white film , marketed under the name Rodinal .
Substance Formula 0 °C 10 °C 20 °C 30 °C 40 °C 50 °C 60 °C 70 °C 80 °C 90 °C 100 °C Barium acetate: Ba(C 2 H 3 O 2) 2: 58.8: 62: 72: 75: 78.5: 77: 75
The three aminophenol isomers: Left: 2-Aminophenol (o-aminophenol) Center: 3-Aminophenol (m-aminophenol) Right: 4-Aminophenol (p-aminophenol) Aminophenol may refer to any of three isomeric chemical compounds: 2-Aminophenol; 3-Aminophenol; 4-Aminophenol; They are simultaneously an aniline and a phenol
3-Aminophenol is an organic compound with formula C 6 H 4 (NH 2)(OH). It is an aromatic amine and a phenol. It is the meta isomer of 2-aminophenol and 4-aminophenol.
This page contains tables of azeotrope data for various binary and ternary mixtures of solvents. The data include the composition of a mixture by weight (in binary azeotropes, when only one fraction is given, it is the fraction of the second component), the boiling point (b.p.) of a component, the boiling point of a mixture, and the specific gravity of the mixture.
The classical methods for the production of paracetamol involve the acetylation of 4-aminophenol with acetic anhydride as the last step. They differ in how 4-aminophenol is prepared. In one method, nitration of phenol with nitric acid affords 4-nitrophenol, which is reduced to 4-aminophenol by hydrogenation over Raney nickel.
The intermediate collapses and expels the leaving group (X) to give the substitution product 3. While nucleophilic acyl substitution reactions can be base-catalyzed, the reaction will not occur if the leaving group is a stronger base than the nucleophile (i.e. the leaving group must have a higher p K a than the nucleophile).
Vapor pressure of acetone based on formula, = + from Lange's Handbook of Chemistry, 10th ed. vapor pressure of acetone (log scale) based on formula, log 10 P m m H g = 7.02447 − 1161.0 224 + T {\displaystyle \scriptstyle \log _{10}P_{mmHg}=7.02447-{\frac {1161.0}{224+T}}} from Lange's Handbook of Chemistry , 10th ed.