Search results
Results from the WOW.Com Content Network
If correctly selected, it reaches terminal velocity, which can be measured by the time it takes to pass two marks on the tube. Electronic sensing can be used for opaque fluids. Knowing the terminal velocity, the size and density of the sphere, and the density of the liquid, Stokes' law can be used to calculate the viscosity of the fluid.
= where is the relaxation time of the particle (the time constant in the exponential decay of the particle velocity due to drag), is the fluid velocity of the flow well away from the obstacle, and is the characteristic dimension of the obstacle (typically its diameter) or a characteristic length scale in the flow (like boundary layer thickness ...
Blue line: drag force; red line: inertia force; black line: total force according to the Morison equation. Note that the inertia force is in front of the phase of the drag force: the flow velocity is a sine wave, while the local acceleration is a cosine wave as a function of time.
Time in force is a measurement of how long an order will remain active before it’s executed by your broker or it expires. It can give you control over the timing of the trade orders you place ...
For premium support please call: 800-290-4726 more ways to reach us
This example neglects the effects of tire sliding, suspension dipping, real deflection of all ideally rigid mechanisms, etc. Another example of significant jerk, analogous to the first example, is the cutting of a rope with a particle on its end. Assume the particle is oscillating in a circular path with non-zero centripetal acceleration.
The investor lives from time 0 to time T; their wealth at time T is denoted W T. He starts with a known initial wealth W 0 (which may include the present value of wage income). At time t he must choose what amount of his wealth to consume, c t , and what fraction of wealth to invest in a stock portfolio, π t (the remaining fraction 1 − π t ...
The equation of motion for Stokes flow can be obtained by linearizing the steady state Navier–Stokes equations.The inertial forces are assumed to be negligible in comparison to the viscous forces, and eliminating the inertial terms of the momentum balance in the Navier–Stokes equations reduces it to the momentum balance in the Stokes equations: [1]