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Intersecting the n-ball with the (n − 2)-dimensional plane defined by fixing a radius and an azimuth gives an (n − 2)-ball of radius √ R 2 − r 2. The volume of the ball can therefore be written as an iterated integral of the volumes of the (n − 2)-balls over the possible radii and azimuths:
In Euclidean n-space, an (open) n-ball of radius r and center x is the set of all points of distance less than r from x.A closed n-ball of radius r is the set of all points of distance less than or equal to r away from x.
The Holmes–Thompson volume of a measurable set in a normed space (, ‖ ‖) is defined as the 2n-dimensional measure of the product set , where is the dual unit ball of ‖ ‖ (the unit ball of the dual norm ‖ ‖).
Consider the linear subspace of the n-dimensional Euclidean space R n that is spanned by a collection of linearly independent vectors , …,. To find the volume element of the subspace, it is useful to know the fact from linear algebra that the volume of the parallelepiped spanned by the is the square root of the determinant of the Gramian matrix of the : (), = ….
Two common methods for finding the volume of a solid of revolution are the disc method and the shell method of integration.To apply these methods, it is easiest to draw the graph in question; identify the area that is to be revolved about the axis of revolution; determine the volume of either a disc-shaped slice of the solid, with thickness δx, or a cylindrical shell of width δx; and then ...
Carom balls. Four-ball needs an additional object ball.. In the realm of carom billiards games, three balls are used to play most games on pocketless billiards tables.Carom balls are not numbered, and are 61–61.5 mm (approximately 2 + 13 ⁄ 32 in) in diameter, and a weight ranging between 205 and 220 grams (7.2 and 7.8 oz) with a typical weight of 210 g (7.5 oz). [10]
When applying prefixes to units of volume, which are expressed in units of length cubed, the cube operators are applied to the unit of length including the prefix. An example of converting cubic centimetre to cubic metre is: 2.3 cm 3 = 2.3 (cm) 3 = 2.3 (0.01 m) 3 = 0.0000023 m 3 (five zeros). [18]: 143
The ideal gas equation can be rearranged to give an expression for the molar volume of an ideal gas: = = Hence, for a given temperature and pressure, the molar volume is the same for all ideal gases and is based on the gas constant: R = 8.314 462 618 153 24 m 3 ⋅Pa⋅K −1 ⋅mol −1, or about 8.205 736 608 095 96 × 10 −5 m 3 ⋅atm⋅K ...