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The Modulus is the remainder of the euclidean division of one number by another. % is called the modulo operation. For instance, 9 divided by 4 equals 2 but it remains 1. Here, 9 / 4 = 2 and 9 % 4 = 1. In your example: 5 divided by 7 gives 0 but it remains 5 (5 % 7 == 5). Calculation. The modulo operation can be calculated using this equation:
Modulus is just the remainder in division before its used in a decimal quotient. Example: The division of two numbers is often expressed as a decimal number (quotient). But the result of the division of say, 1/3, can also be expressed in whole numbers as "0 with a remainder of 1". But that form of quotient is not very helpful in modern math, so ...
If you don't care too much about performance and want to use the straightforward way, you can use either DIV or IDIV. DIV or IDIV takes only one operand where it divides a certain register with this operand, the operand can be register or memory location only. When operand is a byte: AL = AL / operand, AH = remainder (modulus).
64. There is only a simple way to find modulo of 2^i numbers using bitwise. There is an ingenious way to solve Mersenne cases as per the link such as n % 3, n % 7... There are special cases for n % 5, n % 255, and composite cases such as n % 6. For cases 2^i, ( 2, 4, 8, 16 ...) n % 2^i = n & (2^i - 1) More complicated ones are hard to explain.
return std::fmod(std::fmod(x, y) + y, y); } It will always return a positive number if x is negative or positive. Note that if y is negative, the returned value will be negative. If you need a function that will return a positive in any case, then one need to use std::fabs() on y, i.e.: inline double nmod2(double x, double y) {.
14. At least in C++ and Java, modulo (%) has the same level of precedence as multiplication and division. Since %, / and * are (usually) left-associative, they are evaluated left to right. (Thanks to Mark for pointing out operator associativity) In the absence of parentheses, operators of the same level of precedence are simply evaluated left ...
In a boolean context, a result of an expression that's zero is interpreted as a false value, and any non-zero result as a true value. So, in this case, if the result of the modulus operator is not 0, the if expression evaluates to true. I believe some C compilers/standards allow it to output -1 if input is negative.
consider : int 32 bit and long long int of 64 bits. Yes, %(modulo) operator isn't work with floats and double.. if you want to do the modulo operation on large number you can check long long int(64bits) might this help you.
It all falls back to the definition of modulus: It is the remainder, for example, 7 mod 3 = 1. This because 7 = 3(2) + 1, in which 1 is the remainder. To do this process on a simple calculator do the following: Take the dividend (7) and divide by the divisor (3), note the answer and discard all the decimals -> example 7/3 = 2.3333333, only ...
The advantage is that a mod n is a repeated sawtooth graph when a is increasing even through zero, which is important in some calculations. The rem operator gives the remainder for the regular integer division a / n that rounds towards 0 (truncated division), so a = (a / n) * n + (a rem n). edited Sep 16, 2014 at 19:21.