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  2. Greedy algorithm for Egyptian fractions - Wikipedia

    en.wikipedia.org/wiki/Greedy_algorithm_for...

    The simplest fraction ⁠ 3 / y ⁠ with a three-term expansion is ⁠ 3 / 7 ⁠. A fraction ⁠ 4 / y ⁠ requires four terms in its greedy expansion if and only if y ≡ 1 or 17 (mod 24), for then the numerator −y mod x of the remaining fraction is 3 and the denominator is 1 (mod 6). The simplest fraction ⁠ 4 / y ⁠ with a four-term ...

  3. Erdős–Graham problem - Wikipedia

    en.wikipedia.org/wiki/Erdős–Graham_problem

    In combinatorial number theory, the Erdős–Graham problem is the problem of proving that, if the set {,,, …} of integers greater than one is partitioned into finitely many subsets, then one of the subsets can be used to form an Egyptian fraction representation of unity.

  4. Egyptian fraction - Wikipedia

    en.wikipedia.org/wiki/Egyptian_fraction

    These include problems of bounding the length or maximum denominator in Egyptian fraction representations, finding expansions of certain special forms or in which the denominators are all of some special type, the termination of various methods for Egyptian fraction expansion, and showing that expansions exist for any sufficiently dense set of ...

  5. List of logic symbols - Wikipedia

    en.wikipedia.org/wiki/List_of_logic_symbols

    In logic, a set of symbols is commonly used to express logical representation. The following table lists many common symbols, together with their name, how they should be read out loud, and the related field of mathematics.

  6. Erdős–Straus conjecture - Wikipedia

    en.wikipedia.org/wiki/Erdős–Straus_conjecture

    As with fractions of the form , it has been conjectured that every fraction (for >) can be expressed as a sum of three positive unit fractions. A generalized version of the conjecture states that, for any positive k {\displaystyle k} , all but finitely many fractions k n {\displaystyle {\tfrac {k}{n}}} can be expressed as a sum of three ...

  7. “Vanderpump Rules”' James Kennedy Appears to Have Been ...

    www.aol.com/vanderpump-rules-james-kennedy...

    James Kennedy appears to no longer have plans to perform in Las Vegas in the new year.. The DJ, who had three shows slated in January at the famous LIV Nightclub in the Fontainebleau hotel ...

  8. Convicted killer escapes Mississippi prison on Christmas Eve ...

    www.aol.com/convicted-killer-escapes-mississippi...

    The Mississippi Department of Corrections has announced the capture of a convicted killer who escaped on Christmas Eve.

  9. Anthony Richardson's return was exactly what he and the Colts ...

    www.aol.com/sports/anthony-richardsons-return...

    One touchdown turned into three before the end of the day as Richardson’s return to the starting lineup resulted in a 28-27 victory over the Jets and arguably his best game as a professional ...

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