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1 152 921 504 606 846 976 bytes = 1 exabyte [5] or exbibyte. 2 63 = 9 223 372 036 854 775 808 The number of non-negative values for a signed 64-bit integer. 2 63 − 1, a common maximum value (equivalently the number of positive values) for a signed 64-bit integer in programming languages. 2 64 = 18 446 744 073 709 551 616
When expressed as exponents, the geometric series is: 2 0 + 2 1 + 2 2 + 2 3 + ... and so forth, up to 2 63. The base of each exponentiation, "2", expresses the doubling at each square, while the exponents represent the position of each square (0 for the first square, 1 for the second, and so on.). The number of grains is the 64th Mersenne number.
Proof: 2 p+1 ≡ 2 (mod q), so 2 1 / 2 (p+1) is a square root of 2 mod q. By quadratic reciprocity, every prime modulus in which the number 2 has a square root is congruent to ±1 (mod 8). A Mersenne prime cannot be a Wieferich prime. Proof: We show if p = 2 m − 1 is a Mersenne prime, then the congruence 2 p−1 ≡ 1 (mod p 2) does ...
Computing – Computational limit of a 64-bit CPU: 9,223,372,036,854,775,807 (about 9.22 × 10 18) is equal to 2 63 −1, and as such is the largest number which can fit into a signed (two's complement) 64-bit integer on a computer. Mathematics – NCAA basketball tournament: There are 9,223,372,036,854,775,808 (2 63) possible ways to enter the ...
A list of articles about numbers (not about numerals). Topics include powers of ten, notable integers, prime and cardinal numbers, and the myriad system.
Move over, Wordle, Connections and Mini Crossword—there's a new NYT word game in town! The New York Times' recent game, "Strands," is becoming more and more popular as another daily activity ...
For an ANSI/ISO compliant compiler, the minimum requirements for the specified ranges, that is, −(2 63 −1) [11] to 2 63 −1 for signed and 0 to 2 64 −1 for unsigned, [12] must be fulfilled; however, extending this range is permitted. [17] [18] This can be an issue when exchanging code and data between platforms, or doing direct hardware ...
Take each digit of the number (371) in reverse order (173), multiplying them successively by the digits 1, 3, 2, 6, 4, 5, repeating with this sequence of multipliers as long as necessary (1, 3, 2, 6, 4, 5, 1, 3, 2, 6, 4, 5, ...), and adding the products (1×1 + 7×3 + 3×2 = 1 + 21 + 6 = 28). The original number is divisible by 7 if and only if ...