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121 645 100 408 832 000: 20: 2 432 902 008 176 640 000: 25 1.551 121 004 × 10 25: 50 3.041 409 320 × 10 64: 70 1.197 857 167 × 10 100: 100 9.332 621 544 × 10 157: 450 1.733 368 733 × 10 1 000: 1 000: 4.023 872 601 × 10 2 567: 3 249: 6.412 337 688 × 10 10 000: 10 000: 2.846 259 681 × 10 35 659: 25 206: 1.205 703 438 × 10 100 000: 100 ...
The decay time for a supermassive black hole of roughly 1 galaxy-mass (10 11 solar masses) due to Hawking radiation is on the order of 10 100 years. [7] Therefore, the heat death of an expanding universe is lower-bounded to occur at least one googol years in the future. A googol is considerably smaller than a centillion. [8]
For arbitrarily greater numbers one has to choose a base for representing individual digits, say decimal, and provide a separating mark between them (for instance by subscripting each digit by its base, also given in decimal, like 2 4 0 3 1 2 0 1, this number also can be written as 2:0:1:0!). In fact the factorial number system itself is not ...
For =, the sum of the factorials of the digits is simply the number of digits in the base 2 representation since ! =! =. A natural number n {\displaystyle n} is a sociable factorion if it is a periodic point for SFD b {\displaystyle \operatorname {SFD} _{b}} , where SFD b k ( n ) = n {\displaystyle \operatorname {SFD} _{b}^{k}(n)=n} for a ...
The first: 2, 6, 30, 210, 2310, 30030, 510510, 9699690, 223092870, 6469693230, 200560490130, 7420738134810 (sequence A002110 in the OEIS). 1# = 1 is sometimes included. A factorial x ! is the product of all numbers from 1 to x .
The interaction of two factors with s 1 and s 2 levels, respectively, has (s 1 −1)(s 2 −1) degrees of freedom. The formula for more than two factors follows this pattern. In the 2 × 3 example above, the degrees of freedom for the two main effects and the interaction — the number of columns for each — are 1, 2 and 2, respectively.
Stirling permutations, permutations of the multiset of numbers 1, 1, 2, 2, ..., k, k in which each pair of equal numbers is separated only by larger numbers, where k = n + 1 / 2 . The two copies of k must be adjacent; removing them from the permutation leaves a permutation in which the maximum element is k − 1 , with n positions into ...
As one special case, it can be used to prove that if n is a positive integer then 4 divides () if and only if n is not a power of 2. It follows from Legendre's formula that the p -adic exponential function has radius of convergence p − 1 / ( p − 1 ) {\displaystyle p^{-1/(p-1)}} .