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Calorie (15°C) Cal-15 (kg-cal-15) Cal 15: 1.0 ... Mcal-15 (g-cal-15) Mcal 15: 1.0 Mcal 15 (4.2 MJ) kilocalorie (15°C) kcal-15 (g-cal-15) kcal 15: 1.0 ...
Alcohol in food contains 7 kcal/g. [30] The "large" unit is also used to express recommended nutritional intake or consumption, as in "calories per day". Dieting is the practice of eating food in a regulated way to decrease, maintain, or increase body weight , or to prevent and treat diseases such as diabetes and obesity .
1 cal / °C⋅g = 1 Cal / °C⋅kg = 1 kcal / °C⋅kg = 4184 J / kg⋅K [20] = 4.184 kJ / kg⋅K . Note that while cal is 1 ⁄ 1000 of a Cal or kcal, it is also per gram instead of kilo gram : ergo, in either unit, the specific heat capacity of water is approximately 1.
A moderate energy density would be 1.6 to 3 calories per gram (7–13 kJ/g); salmon, lean meat, and bread would fall in this category. Foods with high energy density have more than three calories per gram (>13 kJ/g) and include crackers, cheese, chocolate, nuts, [10] and fried foods like potato or tortilla chips.
These estimates are for a "reference woman" who is 1.63 m (5 ft 4 in) tall and weighs 57 kg (126 lb) and a "reference man" who is 1.78 m (5 ft 10 in) tall and weighs 70 kg (154 lb). [19] Because caloric requirements vary by height, activity, age, pregnancy status, and other factors, the USDA created the DRI Calculator for Healthcare ...
[6] [7] By convention, 1 MET is considered equivalent to the consumption of 3.5 ml O 2 ·kg −1 ·min −1 (or 3.5 ml of oxygen per kilogram of body mass per minute) and is roughly equivalent to the expenditure of 1 kcal per kilogram of body weight per hour. This value was first experimentally derived from the resting oxygen consumption of a ...
1.7×10 −21 J 1 kJ/mol, converted to energy per molecule [9] 2.1×10 −21 J Thermal energy in each degree of freedom of a molecule at 25 °C (kT/2) (0.01 eV) [10] 2.856×10 −21 J By Landauer's principle, the minimum amount of energy required at 25 °C to change one bit of information 3–7×10 −21 J
For example, the freezing point of water is 0 °C and 32 °F, and a 5 °C change is the same as a 9 °F change. Thus, to convert from units of Fahrenheit to units of Celsius, one subtracts 32 °F (the offset from the point of reference), divides by 9 °F and multiplies by 5 °C (scales by the ratio of units), and adds 0 °C (the offset from the ...