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The simplest form goes through the whole list each time: procedure cocktailShakerSort(A : list of sortable items) is do swapped := false for each i in 0 to length(A) − 1 do: if A[i] > A[i + 1] then // test whether the two elements are in the wrong order swap(A[i], A[i + 1]) // let the two elements change places swapped := true end if end for if not swapped then // we can exit the outer loop ...
Swap the first element of the array (the largest element in the heap) with the final element of the heap. Decrease the considered range of the heap by one. Call the siftDown() function on the array to move the new first element to its correct place in the heap. Go back to step (2) until the remaining array is a single element.
It works by taking elements from the list one by one and inserting them in their correct position into a new sorted list similar to how one puts money in their wallet. [22] In arrays, the new list and the remaining elements can share the array's space, but insertion is expensive, requiring shifting all following elements over by one.
In the second (heap shrinking) phase, the maximal node is detached from the end of the array (without needing to move it) and the heap invariants are re-established among its children. (Specifically, among the newly created stepsons.) Practical implementation frequently needs to compute Leonardo numbers L(k). Dijkstra provides clever code which ...
A typical alternative for dense array storage is to use Iliffe vectors, which typically store pointers to elements in the same row contiguously (like row-major order), but not the rows themselves. They are used in (ordered by age): Java, [14] C#/CLI/.Net, Scala, [15] and Swift.
Bubble sort, sometimes referred to as sinking sort, is a simple sorting algorithm that repeatedly steps through the input list element by element, comparing the current element with the one after it, swapping their values if needed. These passes through the list are repeated until no swaps have to be performed during a pass, meaning that the ...
The best case input is an array that is already sorted. In this case insertion sort has a linear running time (i.e., O(n)). During each iteration, the first remaining element of the input is only compared with the right-most element of the sorted subsection of the array. The simplest worst case input is an array sorted in reverse order.
The removed element is the overall winner. Therefore, it has won each game on the path from the input array to the root. When selecting a new element from the input array, the element needs to compete against the previous losers on the path to the root. When using a loser tree, the partner for replaying the games is already stored in the nodes.