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2 Other equations. Toggle Other equations subsection. 2.1 Mathematics. 2.2 Physics. 2.3 Chemistry. 2.4 Telecommunications engineering. 3 Lists of equations. 4 See also.
Many mathematical problems have been stated but not yet solved. These problems come from many areas of mathematics, such as theoretical physics, computer science, algebra, analysis, combinatorics, algebraic, differential, discrete and Euclidean geometries, graph theory, group theory, model theory, number theory, set theory, Ramsey theory, dynamical systems, and partial differential equations.
Of the cleanly formulated Hilbert problems, numbers 3, 7, 10, 14, 17, 18, 19, and 20 have resolutions that are accepted by consensus of the mathematical community. Problems 1, 2, 5, 6, [g] 9, 11, 12, 15, 21, and 22 have solutions that have partial acceptance, but there exists some controversy as to whether they resolve the problems.
A mathematical constant is a key number whose value is fixed by an unambiguous definition, often referred to by a symbol (e.g., an alphabet letter), or by mathematicians' names to facilitate using it across multiple mathematical problems. [1]
The real part of every nontrivial zero of the Riemann zeta function is 1/2. The Riemann hypothesis is that all nontrivial zeros of the analytical continuation of the Riemann zeta function have a real part of 1 / 2 . A proof or disproof of this would have far-reaching implications in number theory, especially for the distribution of prime ...
1. Denotes subtraction and is read as minus; for example, 3 – 2. 2. Denotes the additive inverse and is read as minus, the negative of, or the opposite of; for example, –2. 3. Also used in place of \ for denoting the set-theoretic complement; see \ in § Set theory. × (multiplication sign) 1.
2 c. unsweetened soy milk, plus more for thinning. 1 1/2 c. whole milk Greek yogurt. 3 tsp. pure maple syrup. 2 tsp. ground cinnamon. 1 1/2 tsp. pure vanilla extract. 1/2 tsp. kosher salt. 1 1/4 c ...
Starting state of the standard puzzle; a jug filled with 8 units of water, and two empty jugs of sizes 5 and 3. The solver must pour the water so that the first and second jugs both contain 4 units, and the third is empty.