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Wildcard mask bit 0 – Matches the corresponding bit value in the address. Wildcard mask bit 1 – Ignores the corresponding bit value in the address. The easiest method for calculating a wildcard mask is to subtract the network subnet mask from 255.255.255.255, as shown for /24 and /26 subnet masks in the figure.
Because 2 bits are borrowed, the new subnet mask would be /26 or 255.255.255.192 Exam with this question: CCNA 1 v7 Modules 11 – 13 Exam Answers Exam with this question: CyberOps Associate Course Final Exam Answers
Explanation: The 172.16.16.0/22 network has 22 bits in the network portion and 10 bits in the host portion. . Converting the network address to binary yields a subnet mask of 255.255.
Explanation: The calculation should start with the IPv4 prefix 10.25.0.0/16, a subnet mask of 255.255.255.128 is required to create 512 subnets, each can accommodate at least 100 hosts. The subnet mask 255.255.255.128 is equivalent to the notation of /25. The difference between /16 and /25 is 9 bits. 9 bits will produce 512 subnets.
A /28 mask is the same as 255.255.255.240. This leaves 4 host bits. With 4 host bits, 16 IP addresses are possible, but one address represents the subnet number and one address represents the broadcast address. 14 addresses can then be used to assign to network devices.
255.255.255.240; 255.255.255.224; Explanation: The largest subnet in the topology has 100 hosts in it so the subnet mask must have at least 7 host bits in it (27-2=126). 255.255.255.0 has 8 hosts bits, but this does not meet the requirement of providing the maximum number of subnets. Exam with this question: CCNA 1 v7 Course Final Exam Answers
Explanation: The binary format for 255.255.255.224 is 11111111.11111111.11111111.11100000. The prefix length is the number of consecutive 1s in the subnet mask. Therefore, the prefix length is /27. Refer to the exhibit. A network administrator is connecting a new host to the Medical LAN. The host needs to communicate with remote networks.
Explanation: From the subnet mask of 255.255.255.240 (/28) we learn there are 24 – 2 = 14 hosts per subnet. Exam with this question: CCNA v3.0 (200-125) Study Guide – Exam Dumps Please login or Register to submit your answer
255.255.255.240; 255.255.255.248; 255.255.255.252; Explanation: If the same mask is to be used, then the network with the most hosts must be examined for number of hosts. Because this is 10 hosts, 4 host bits are needed. The /28 or 255.255.255.240 subnet mask would be appropriate to use for these networks.
Finally, 255.255.255.240 represents 4 host bits. Exam with this question: CCNA 1 v7 Checkpoint Exam: IP Addressing Exam Answers Exam with this question: Network Addressing and Basic Troubleshooting Final Exam