Search results
Results from the WOW.Com Content Network
In mathematics, the Fibonacci sequence is a sequence in which each number is the sum of the two preceding ones. Numbers that are part of the Fibonacci sequence are known as Fibonacci numbers, commonly denoted Fn . Many writers begin the sequence with 0 and 1, although some authors start it from 1 and 1 [1][2] and some (as did Fibonacci) from 1 ...
Simple quintuple meter can be written in 5. 4 or 5. 8 time, but may also be notated by using regularly alternating bars of triple and duple meters, for example 2. 4 + 3. 4. Compound quintuple meter, with each of its five beats divided into three parts, can similarly be notated using a time signature of 15. 8, by writing triplets on each beat of ...
This is a list of musical compositions or pieces of music that have unusual time signatures. "Unusual" is here defined to be any time signature other than simple time signatures with top numerals of 2, 3, or 4 and bottom numerals of 2, 4, or 8, and compound time signatures with top numerals of 6, 9, or 12 and bottom numerals 4, 8, or 16.
A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2. Such a triple is commonly written (a, b, c), a well-known example is (3, 4, 5). If (a, b, c) is a Pythagorean triple, then so is (ka, kb, kc) for any positive integer k. A triangle whose side lengths are a Pythagorean triple is a right triangle and ...
φ(n) is the number of positive integers not greater than n that are coprime with n. A000010. Lucas numbers L(n) 2, 1, 3, 4, 7, 11, 18, 29, 47, 76, ... L(n) = L(n − 1) + L(n − 2) for n ≥ 2, with L(0) = 2 and L(1) = 1. A000032. Prime numbers pn. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, ... The prime numbers pn, with n ≥ 1.
Water pouring puzzle. Starting state of the standard puzzle; a jug filled with 8 units of water, and two empty jugs of sizes 5 and 3. The solver must pour the water so that the first and second jugs both contain 4 units, and the third is empty. Water pouring puzzles (also called water jug problems, decanting problems, [1][2] measuring puzzles ...
0.231 21 (4) [h] 0.231 53 (4) [i] 1.0 × 10 −3 1.7 × 10 −4 1.7 × 10 −4 [34] [35] [35] electron g-factor: −2.002 319 304 360 92 (36) 1.8 × 10 −13 [36] muon g-factor −2.002 331 841 23 (82) 4.1 × 10 −10 [37] proton g-factor 5.585 694 6893 (16) 2.9 × 10 −10 [38]
If the hundreds digit is odd, the number obtained by the last two digits must be 4 times an odd number. 352: 52 = 4 x 13. Add the last digit to twice the rest. The result must be divisible by 8. 56: (5 × 2) + 6 = 16. The last three digits are divisible by 8. [2][3] 34,152: Examine divisibility of just 152: 19 × 8.