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2. Fraction - Wikipedia

   en.wikipedia.org/wiki/Fraction

   Unit fractions can also be expressed using negative exponents, as in 2 −1, which represents 1/2, and 2 −2, which represents 1/(2 2) or 1/4. A dyadic fraction is a common fraction in which the denominator is a power of two, e.g. ⁠ 1 / 8 ⁠ = ⁠ 1 / 2 3 ⁠. In Unicode, precomposed fraction characters are in the Number Forms block.

3. File:Partial Fraction.pdf - Wikipedia

   en.wikipedia.org/wiki/File:Partial_Fraction.pdf

   You are free: to share – to copy, distribute and transmit the work; to remix – to adapt the work; Under the following conditions: attribution – You must give appropriate credit, provide a link to the license, and indicate if changes were made.

4. Unit fraction - Wikipedia

   en.wikipedia.org/wiki/Unit_fraction

   Slices of approximately 1/8 of a pizza. A unit fraction is a positive fraction with one as its numerator, 1/ n.It is the multiplicative inverse (reciprocal) of the denominator of the fraction, which must be a positive natural number.

5. Fixed-point arithmetic - Wikipedia

   en.wikipedia.org/wiki/Fixed-point_arithmetic

   A fixed-point representation of a fractional number is essentially an integer that is to be implicitly multiplied by a fixed scaling factor. For example, the value 1.23 can be stored in a variable as the integer value 1230 with implicit scaling factor of 1/1000 (meaning that the last 3 decimal digits are implicitly assumed to be a decimal fraction), and the value 1 230 000 can be represented ...

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7. Number Forms - Wikipedia

   en.wikipedia.org/wiki/Number_Forms

   1 ⁄ 7: 0.142... Vulgar Fraction One Seventh 2150 8528 ⅑ 1 ⁄ 9: 0.111... Vulgar Fraction One Ninth 2151 8529 ⅒ 1 ⁄ 10: 0.1 Vulgar Fraction One Tenth 2152 8530 ⅓ 1 ⁄ 3: 0.333... Vulgar Fraction One Third 2153 8531 ⅔ 2 ⁄ 3: 0.666... Vulgar Fraction Two Thirds 2154 8532 ⅕ 1 ⁄ 5: 0.2 Vulgar Fraction One Fifth 2155 8533 ⅖ 2 ...

8. Heaviside cover-up method - Wikipedia

   en.wikipedia.org/wiki/Heaviside_cover-up_method

   Set up a partial fraction for each factor in the denominator. With this framework we apply the cover-up rule to solve for A, B, and C. D 1 is x + 1; set it equal to zero. This gives the residue for A when x = −1. Next, substitute this value of x into the fractional expression, but without D 1. Put this value down as the value of A.

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