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  2. Square pyramid - Wikipedia

    en.wikipedia.org/wiki/Square_pyramid

    A square pyramid has five vertices, eight edges, and five faces. One face, called the base of the pyramid, is a square; the four other faces are triangles. [2] Four of the edges make up the square by connecting its four vertices. The other four edges are known as the lateral edges of the pyramid; they meet at the fifth vertex, called the apex. [3]

  3. Egyptian geometry - Wikipedia

    en.wikipedia.org/wiki/Egyptian_geometry

    Such a formula would be needed for building pyramids. In the next problem (Problem 57), the height of a pyramid is calculated from the base length and the seked (Egyptian for slope), while problem 58 gives the length of the base and the height and uses these measurements to compute the seked.

  4. Gyroelongated square bipyramid - Wikipedia

    en.wikipedia.org/wiki/Gyroelongated_square_bipyramid

    The surface area of a gyroelongated square bipyramid is 16 times the area of an equilateral triangle, that is: [4], and the volume of a gyroelongated square bipyramid is obtained by slicing it into two equilateral square pyramids and one square antiprism, and then adding their volume: [4] + +.

  5. Frustum - Wikipedia

    en.wikipedia.org/wiki/Frustum

    The Egyptians knew the correct formula for the volume of such a truncated square pyramid, but no proof of this equation is given in the Moscow papyrus. The volume of a conical or pyramidal frustum is the volume of the solid before slicing its "apex" off, minus the volume of this "apex":

  6. Pyramid (geometry) - Wikipedia

    en.wikipedia.org/wiki/Pyramid_(geometry)

    The base regularity of a pyramid's base may be classified based on the type of polygon: one example is the star pyramid in which its base is the regular star polygon. [24] The truncated pyramid is a pyramid cut off by a plane; if the truncation plane is parallel to the base of a pyramid, it is called a frustum.

  7. Moscow Mathematical Papyrus - Wikipedia

    en.wikipedia.org/wiki/Moscow_Mathematical_Papyrus

    Problem 14 states that a pyramid has been truncated in such a way that the top area is a square of length 2 units, the bottom a square of length 4 units, and the height 6 units, as shown. The volume is found to be 56 cubic units, which is correct. [1]

  8. Truncated octahedron - Wikipedia

    en.wikipedia.org/wiki/Truncated_octahedron

    Considering that each length of the regular octahedron is , and the edge length of a square pyramid is (the square pyramid is an equilateral, the first Johnson solid). From the equilateral square pyramid's property, its volume is 2 6 a 3 {\textstyle {\tfrac {\sqrt {2}}{6}}a^{3}} .

  9. Square pyramidal number - Wikipedia

    en.wikipedia.org/wiki/Square_pyramidal_number

    A square pyramid of cannonballs at Rye Castle in England 4900 balls arranged as a square pyramid of side 24, and a square of side 70. The cannonball problem asks for the sizes of pyramids of cannonballs that can also be spread out to form a square array, or equivalently, which numbers are both square and square pyramidal. Besides 1, there is ...