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In the apothecaries' system, which was widely used in the United States until the middle of the 20th century, [15] the dram is the mass of 1 ⁄ 96 pounds apothecaries (lb ap), or 1 ⁄ 8 ounces apothecaries (oz ap or ℥) [5]: C-7 (the pound apothecaries and ounce apothecaries are equal to the troy pound (lb t), and troy ounce (oz t ...
The avoirdupois weight system is thought to have come into use in England around 1300. [citation needed] It was originally used for weighing wool. In the early 14th century several other specialized weight systems were used, including the weight system of the Hanseatic League with a 16-ounce pound of 7200 grains and an 8-ounce mark.
The American football field, which has a playing area 100 yards (91.4 m) long by 160 feet (48.8 m) wide. This is often used by the American public media for the sizes of large buildings or parks. It is used both as a unit of length (100 yd or 91.4 m, the length of the playing field excluding goal areas) and as a unit of area (57,600 sq ft or ...
English-speaking countries also used a system of units of fluid measure, or in modern terminology volume units, based on the apothecaries' system. Originally, the terms and symbols used to describe the volume measurements of liquids were the same as or similar to those used to describe weight measurements of solids [33] (for example, the pound by weight and the fluid pint were both referred to ...
A Canadian football field is 65 yards (59 m) wide and 110 yards (100 m) long with end zones adding a combined 40 yards (37 m) to the length, making it 87,750 square feet (8,152 m 2) or 0.8215 ha (2.030 acres).
[6] The statcoulomb (statC) or franklin (Fr) is a unit of electric charge equal to 1 dyn 1/2 ⋅cm, corresponding to ~ 333.564 pC. The statampere (statA) is a unit of electric current equal to 1 statC/s, corresponding to ~ 333.564 pA. The statvolt (statV) is a unit of electric potential difference equal to 1 erg/statC, corresponding to 299.792 ...
The base units are defined in terms of the defining constants. For example, the kilogram is defined by taking the Planck constant h to be 6.626 070 15 × 10 −34 J⋅s, giving the expression in terms of the defining constants [1]: 131 1 kg = (299 792 458) 2 / (6.626 070 15 × 10 −34)(9 192 631 770) h Δν Cs / c 2 .
Since all gases have the same volume per mole at a given temperature and pressure far from their points of liquefaction and solidification (see Perfect gas), and air is about 1 / 5 oxygen (molecular mass 32) and 4 / 5 nitrogen (molecular mass 28), the density of any near-perfect gas relative to air can be obtained to a good ...
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