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you can easily check that bool(0)will be False. with this for instances of int class only 0 will return False. another example= bool([1,2,3]) [1,2,3]has no __bool__()method defined but it has __len__()and since its length is greater than 0, it will return True. Now you can see why empty lists return False.
Some of the operators you may know from other languages have a different name in Python. The logical operators && and || are actually called and and or. Likewise the logical negation operator ! is called not. So you could just write: if len(a) % 2 == 0 and len(b) % 2 == 0: or even: if not (len(a) % 2 or len(b) % 2):
346. To negate a boolean, you can use the not operator: not bool. Or in your case, the if / return blocks can be replaced by: return not bool. Be sure to note the operator precedence rules, and the negated is and in operators: a is not b and a not in b. edited Apr 4, 2022 at 20:57.
This is actually outdated. For Python 3.7+, Argparse now supports boolean args (search BooleanOptionalAction). The implementation looks like this: import argparse ap = argparse.ArgumentParser () # List of args ap.add_argument ('--foo', default=True, type=bool, help='Some helpful text that is not bar.
122. You can change the value of a bool all you want. As for an if: if randombool is True: works, but you can also use: if randombool: If you want to test whether something is false you can use: if randombool is False. but you can also use:
If you have control over the entity that's returning true/false, one option is to have it return 1/0instead of true/false, then: boolean_response = bool(int(response)) The extra cast to inthandles responses from a network, which are always string. Update 2021: "which are always string" -- this is a naive observation.
11. Here's a yet another solution to your problem: def to_bool(s): return 1 - sum(map(ord, s)) % 2. # return 1 - sum(s.encode('ascii')) % 2 # Alternative for Python 3. It works because the sum of the ASCII codes of 'true' is 448, which is even, while the sum of the ASCII codes of 'false' is 523 which is odd.
Convert inputs to booleans. Use the bitwise xor operator (^ or operator.xor) For example, bool(a) ^ bool(b) When you convert the inputs to booleans, bitwise xor becomes logical xor. Note that the accepted answer is wrong: != is not the same as xor in Python because of the subtlety of operator chaining.
The two objects representing the values False and True are the only Boolean objects. The Boolean type is a subtype of the integer type, and Boolean values behave like the values 0 and 1, respectively, in almost all contexts, the exception being that when converted to a string, the strings "False" or "True" are returned, respectively.
To update this for Python-3 you can do this "{} {}".format(True, False) However if you want to actually format the string (e.g. add white space), you encounter Python casting the boolean into the underlying C value (i.e. an int), e.g.