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An adiabatic process is not necessarily isentropic. It is isentropic only if it is reversible. In fact this is a good rule to memorize: $$\text{reversible+adiabatic} = \text{isentropic}$$ Entropy can change even if heat is not exchanged. That's what we call irreversible adiabatic process.
In thermodynamics, an isentropic process is an idealized thermodynamic process that is adiabatic and in which the work transfers of the system are frictionless; there is no transfer of matter and the process is reversible. An isentropic process is, by definition, adiabatic and reversible.
An isentropic process is by definition a process that is both adiabatic and reversible. So you can't have an isentropic process that is not adiabatic. However, you can have an adiabatic process that is not isentropic, if it is not a reversible process. An example is an adiabatic process involving friction losses.
Isentropic processes are ones with constant entropy. Since entropy is defined as dS = dQ/T, then a reversible adiabatic process with dQ = 0 is an isentropic process. Need to take a step back to understand this. First, the physics of waves in gases come from the fluid equations. These include conservation of mass, momentum and energy.
So, a reversible adiabatic process is necessarily isentropic, but irreversible adiabatic processes are not so. To put it in another way, in an irreversible process, according to the above inequality, either entropy changes, or heat must be somehow removed from the system to make it possible to have zero change in entropy.
Equation 1.0 says that is a spontaneous isentropic and isochoric process sees its internal energy decrease. Since the entropy of the system is unchanged, there must be an increase in entropy of the surroundings, which can be achieved only if the energy of the system decreases as energy flows out as heat, but this seems to contradict the fact ...
My question is, I don't see how a change in enthalpy can be equal to work input/output in the isentropic compressor and turbine of a Brayton cycle. Isn't enthalpy only equal to heat added if the process is isobaric? In an isentropic process, the enthalpy change will be equal to the expansion work plus the pressure increase, right? Thanks in ...
An isentropic process, P1=200 psi, P2= 300 psi and T1= 700°R. Find T2 using k= 1.4
Answer to True or false: The isentropic process of an. Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.
Fig 1 compares an isothermal compression to an adiabatic compression that begin at the same pressure for the same volume change. Note that the magnitude of the work (area under the curve) is greater for the adiabatic process than the isothermal process. But since the work is done on the system, the work is negative work.