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DNA restriction. If you have a large DNA molecule, you will probably cut it into smaller fragments using a so-called DNA restriction enzyme. Step 2. Gel electrophoresis. Then you will place properly prepared samples of the nucleic acid solution in the wells of an agarose gel electrophoresis system and apply a voltage for a specified amount of time.
In Double Stranded DNA , Adenine pairs with Thymine as we know, it means amount of A = Amount of T. Here A=35% so T=35%. Total will be 100% (for all 4 bases) , left out is 30 % which will be equally divided by Guanine and Cytocine , hence G=15% and C=15%. A=35% T=35% G=15% C=15%. In Double Stranded DNA , Adenine pairs with Thymine as we know ...
23% DNA is composed of nucleotides - information carrying blocks. The body interprets the information blocks in order to produce proteins and other structures of and for the body. There are 4 nucleotides, and for simplicity sake I'll abbreviate them to single letters: G, C, A, and T (the link below has all this and much much more). Now here's the thing - wherever a G is, there is a C that ...
8% will be thymine. DNA is double stranded and nucleotides always appear in the same pairs: cytosine pairs with guanine (G-C) adenine pairs with thymine (A-T) In this example cytosine makes up 42%, which means that guanine also makes up 42%. So 84% of the DNA is a G-C base pair. This leaves 16% for the A-T base pair: 8% adenine and 8% thymine.
Thymine would be 33 % and cytosine would be 17%. If a sample of DNA contains 33 % adenine then it contains 33% thymine too. Adenine= Thymine (because they are paired together, they are in equal amounts) So, out of 100, adenine and thymine are 66% of nucleotides, which leaves 100-66=34. So, that means guanine and cytosine are 34%.
In this sample, there exist 10% of guanine, therefore there's also 10% of cytosine. Therefore, thymine and adenine would make up a total of 100% −10% − 10% = 80% of the DNA. As they must exist in equal amounts, the percentage of thymine in this DNA sample will be 80% ÷ 2 = 40%. 40% Guanine (G) in DNA is one-to-one coupled to cytosine (C ...
25 Well, we have to know the base pairs for "DNA" first. Adenine only bonds with thymine with two hydrogen bonds, while guanine only bonds with cytosine with three hydrogen bonds. Bonding pairs can also happen vice-versa. Since there are 100 nucleotides in this strand and 25 adenine bases, then that must mean that there are also 25 thymine bases. So, there are a total of 25+25=50 adenine and ...
Since you have 35 C, you will have 35 G. Without knowing the number of thymine, the number of adenine is unknown . That is all the information you can get from this. Just because there are 35 C and G, there doesn't have to be an equal number of A and T. Answer link. You must learn by reading and understanding what the concepts are that you have ...
DF = V f V i. EXAMPLE 1: What is the dilution factor if you add a 0.1 mL aliquot of a specimen to 9.9 mL of diluent? Solution: V f = aliquot volume + diluent volume = (0.1 + 9.9) mL = 10.0 mL. DF = V f V i = 10.0mL 0.1mL = 100. You have diluted the sample by a factor of 100. The dilution factor is often used as the denominator of a fraction.
To cut DNA, RNA, or plasmid at restriction sites (like EcoRI, BamHI, hindIII and BglII) to create smaller genetic fragments that can be separated and thus characterized using gel electrophoresis. There exist an enzyme, called restriction enzyme, that can identify a particular nucleotide sequence, called restriction sites, and perform cleaving operation. This process separates genetic material ...