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find_character(string,char) returns integer Description Returns the position of the start of the first occurrence of the character char in string. If the character is not found most of these routines return an invalid index value – -1 where indexes are 0-based, 0 where they are 1-based – or some value to be interpreted as Boolean FALSE.
This comparison of programming languages (strings) compares the features of string data structures or text-string processing for over 52 various computer programming languages. Concatenation [ edit ]
AutoHotkey: As the first character of continued line; any expression operators except ++ and --, and a comma or a period [7] Some form of line comment serves as line continuation. Turbo Assembler: \ m4: dnl; TeX: % Character position. Fortran 77: A non-comment line is a continuation of the prior non-comment line if any non-space character ...
Without interning, comparing two distinct strings may involve examining every character of both. [ Note 1 ] This is slow for several reasons: it is inherently O(n) in the length of the strings; it typically requires reads from several regions of memory , which take time; and the reads fill up the processor cache, meaning there is less cache ...
This comparison of programming languages compares how object-oriented programming languages such as C++, Java, Smalltalk, Object Pascal, Perl, Python, and others manipulate data structures. Object construction and destruction
In computer programming, a naming convention is a set of rules for choosing the character sequence to be used for identifiers which denote variables, types, functions, and other entities in source code and documentation. Reasons for using a naming convention (as opposed to allowing programmers to choose any character sequence) include the ...
In computer science, a three-way comparison takes two values A and B belonging to a type with a total order and determines whether A < B, A = B, or A > B in a single operation, in accordance with the mathematical law of trichotomy.
compare two floats, 1 on NaN fcmpl 95 1001 0101 value1, value2 → result compare two floats, -1 on NaN fconst_0 0b 0000 1011 → 0.0f push 0.0f on the stack fconst_1 0c 0000 1100 → 1.0f push 1.0f on the stack fconst_2 0d 0000 1101 → 2.0f push 2.0f on the stack fdiv 6e 0110 1110 value1, value2 → result divide two floats fload 17 0001 0111