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The solver is given a grid and a list of words. To solve the puzzle correctly, the solver must find a solution that fits all of the available words into the grid. [1] [2] [8] [9] Generally, these words are listed by number of letters, and further alphabetically. [2] [8] Many times, one word is filled in for the solver to help them begin the ...
The solution to the meta is a similar phrase in which the middle word is "or": "FIGHT OR FLIGHT". Since September 2015, the Wall Street Journal Friday crossword has featured a crossword contest metapuzzle, with the prize of a WSJ mug going to a reader randomly chosen from among those submitting the correct answer. [16] [17]
You can also select any square in the crossword grid and click the square again to swap between highlighting Across and Down clues. Type in the missing letters to fill in the answer. You can check any letter, answer, or the full grid at any time with the Check button. Correct letters will become green while wrong ones will be marked with a red ...
For every 3 non-theme words you find, you earn a hint. Hints show the letters of a theme word. If there is already an active hint on the board, a hint will show that word’s letter order.
The answer to the clue is generally a pun of some sort. A weekly "kids version" of the puzzle features a three-letter word plus three four-letter words. In order to find the letters that are in the answer to the given clue, the player must unscramble all four of the scrambled words; the letters that are in the clue will be circled.
fuel filling station, e.g. "a Texaco garage" (also petrol station, US: gas station) a genre of music place where vehicles are repaired; building attached to or in the grounds of a residence for storing a car (parking garage) building serving as a public parking facility (UK: multistorey car park or just multistorey) garbage (n.)
The apparent paradox is explained by the fact that the side of the new large square is a little smaller than the original one. If θ is the angle between two opposing sides in each quadrilateral, then the ratio of the two areas is given by sec 2 θ. For θ = 5°, this is approximately 1.00765, which corresponds to a difference of about 0.8%.
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