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  2. Clearing denominators - Wikipedia

    en.wikipedia.org/wiki/Clearing_denominators

    The first step is to determine a common denominator D of these fractions – preferably the least common denominator, which is the least common multiple of the Q i. This means that each Q i is a factor of D, so D = R i Q i for some expression R i that is not a fraction. Then

  3. Lowest common denominator - Wikipedia

    en.wikipedia.org/wiki/Lowest_common_denominator

    It is usually easiest to add, subtract, or compare fractions when each is expressed with the same denominator, called a "common denominator". For example, the numerators of fractions with common denominators can simply be added, such that + = and that <, since each fraction has the common denominator 12.

  4. Fraction - Wikipedia

    en.wikipedia.org/wiki/Fraction

    To change a common fraction to a decimal, do a long division of the decimal representations of the numerator by the denominator (this is idiomatically also phrased as "divide the denominator into the numerator"), and round the answer to the desired accuracy. For example, to change1 / 4 ⁠ to a decimal, divide 1.00 by 4 (" 4 into 1.00 ...

  5. Least common multiple - Wikipedia

    en.wikipedia.org/wiki/Least_common_multiple

    The least common multiple of the denominators of two fractions is the "lowest common denominator" (lcd), and can be used for adding, subtracting or comparing the fractions. The least common multiple of more than two integers a , b , c , . . . , usually denoted by lcm( a , b , c , . . .) , is defined as the smallest positive integer that is ...

  6. Today’s NYT ‘Strands’ Hints, Spangram and Answers for ...

    www.aol.com/today-nyt-strands-hints-spangram...

    Related: 300 Trivia Questions and Answers to Jumpstart Your Fun Game Night What Is Today's Strands Hint for the Theme: "Board Certified"? Today's Strands game revolves around a craft that involves ...

  7. Continued fraction - Wikipedia

    en.wikipedia.org/wiki/Continued_fraction

    where c 1 = ⁠ 1 / a 1 ⁠, c 2 = ⁠ a 1 / a 2 ⁠, c 3 = ⁠ a 2 / a 1 a 3 ⁠, and in general c n+1 = ⁠ 1 / a n+1 c n ⁠. Second, if none of the partial denominators b i are zero we can use a similar procedure to choose another sequence {d i} to make each partial denominator a 1:

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