Search results
Results from the WOW.Com Content Network
Alkaline water electrolysis is a type of electrolysis that is characterized by having two electrodes operating in a liquid alkaline electrolyte. Commonly, a solution of potassium hydroxide (KOH) or sodium hydroxide (NaOH) at 25-40 wt% is used. [6]
The catalytic performance of Mo3P nanoparticles is tested in the hydrogen evolution reaction (HER), indicating an onset potential of as low as 21 mV, H2 formation rate, and exchange current density of 214.7 μmol/(s·g) cat (at only 100 mV overpotential) and 279.07 μA/cm 2, respectively, which are among the closest values yet observed to platinum.
About 112 g of KOH dissolve in 100 mL water at room temperature, which contrasts with 100 g/100 mL for NaOH. [14] Thus on a molar basis, KOH is slightly more soluble than NaOH. Lower molecular-weight alcohols such as methanol, ethanol, and propanols are also excellent solvents. They participate in an acid-base equilibrium.
NaOH −469.15 Sodium hydroxide: Solid NaOH −425.93 Sodium hypochlorite: Solid NaOCl −347.1 Sodium nitrate: Aqueous NaNO 3: −446.2 Sodium nitrate: Solid NaNO 3: −424.8 Sodium oxide: Solid Na 2 O −414.2 Sulfur (monoclinic) Solid S 8: 0.3 Sulfur (rhombic) Solid S 8: 0 Hydrogen sulfide: Gas H 2 S −20.63 Sulfur dioxide: Gas SO 2: −296 ...
KHP K + + HP −. and then, acting as a weak acid, hydrogen phthalate reacts reversibly with water to give hydronium (H 3 O +) and phthalate ions. HP − + H 2 O ⇌ P 2− + H 3 O + KHP can be used as a buffering agent in combination with hydrochloric acid (HCl) or sodium hydroxide (NaOH). The buffering region is dependent upon the pKa, and is ...
InChI=1S/Li.H2O/h; 1H2/q+1;/p-1 Key ... Li 2 SO 4 + 2 NaOH → Na 2 SO 4 + 2 LiOH. The main by-products are gypsum and sodium sulphate, which have some market value ...
Because Sr(OH) 2 is slightly soluble in cold water, its preparation can be easily carried out by the addition of a strong base such as NaOH or KOH, drop by drop to a solution of any soluble strontium salt, most commonly Sr(NO 3) 2 (strontium nitrate). The Sr(OH) 2 will precipitate out as a fine white powder.
pH = 1 / 2 pK w + 1 / 2 log (1 + T A / K a ) With a dilute solution of the weak acid, the term 1 + T A / K a is equal to T A / K a to a good approximation. If pK w = 14, pH = 7 + (pK a + log T A)/2. This equation explains the following facts: The pH at the end-point depends mainly on the strength of the ...