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2. 20 Cleaning Products That Are a Complete Waste of Money - AOL

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   Over a year, you'd be using more than $100 worth of wipes at that rate — ouch — and putting more than two dozen plastic canisters in the trash. Try this instead: Assess whether you really need ...

3. California Redemption Value - Wikipedia

   en.wikipedia.org/wiki/California_Redemption_Value

   The symbol on beverage containers eligible for reimbursement is "CA CRV". Currently, CRV is 5 cents for containers less than 24 US fluid ounces (710 ml) and 10 cents for containers 24 US fluid ounces (710 ml) or larger. [5] Starting in 2024 wine boxes, pouches and bladders can be redeemed for 25 cents.

4. Drum (container) - Wikipedia

   en.wikipedia.org/wiki/Drum_(container)

   The compression stability of plastic drums can be sensitive to heat. The Plastic Drum Institute does not recommend stacking when temperatures are above about 32 °C (90 °F). [23] Some methods of reinforcing the sidewalls are available. [24] [25] Plastic drums are used for more than shipping containers. They can be used for water collection and ...

5. Sales taxes in the United States - Wikipedia

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   On January 1, 2012, Montgomery County began levying a 5-cent-per-bag tax on plastic and paper bags provided by retailers at the point of sale, pickup, or delivery (with few exceptions, most notably bags for loose produce in grocery stores, bags for prescription drugs, and paper bags at fast-food restaurants). Four cents of this tax goes to the ...

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   AOL latest headlines, entertainment, sports, articles for business, health and world news.

7. AOL Mail

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   Get AOL Mail for FREE! Manage your email like never before with travel, photo & document views. Personalize your inbox with themes & tabs. You've Got Mail!

8. Coupon collector's problem - Wikipedia

   en.wikipedia.org/wiki/Coupon_collector's_problem

   An alternative statement is: given n coupons, how many coupons do you expect you need to draw with replacement before having drawn each coupon at least once? The mathematical analysis of the problem reveals that the expected number of trials needed grows as Θ ( n log ⁡ ( n ) ) {\displaystyle \Theta (n\log(n))} .

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