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Shape of water molecule showing that the real bond angle 104.5° deviates from the ideal sp 3 angle of 109.5°.. In chemistry, Bent's rule describes and explains the relationship between the orbital hybridization and the electronegativities of substituents.
The angle between any two bonds is the tetrahedral bond angle of 109°28' [3] (around 109.5°). Pauling supposed that in the presence of four hydrogen atoms, the s and p orbitals form four equivalent combinations which he called hybrid orbitals. Each hybrid is denoted sp 3 to indicate its composition, and is directed along one of the four C–H ...
2 O is sp 3 hybridized in which the 2s atomic orbital and the three 2p orbitals of oxygen are hybridized to form four new hybridized orbitals which then participate in bonding by overlapping with the hydrogen 1s orbitals. As such, the predicted shape and bond angle of sp 3 hybridization is tetrahedral and 109.5°. This is in open agreement with ...
This would result in the geometry of a regular tetrahedron with each bond angle equal to arccos(− 1 / 3 ) ≈ 109.5°. However, the three hydrogen atoms are repelled by the electron lone pair in a way that the geometry is distorted to a trigonal pyramid (regular 3-sided pyramid) with bond angles of 107°.
The carbon–carbon single bond is a sigma bond and is formed between one hybridized orbital from each of the carbon atoms. In ethane, the orbitals are sp 3-hybridized orbitals, but single bonds formed between carbon atoms with other hybridizations do occur (e.g. sp 2 to sp 2). In fact, the carbon atoms in the single bond need not be of the ...
In these compounds, it is not possible for the carbon atoms to assume the 109.5° bond angles with standard sp 3 hybridization. Increasing the p-character to sp 5 (i.e. 1 ⁄ 6 s-density and 5 ⁄ 6 p-density) [5] makes it possible to reduce the bond angles to 60°. At the same time, the carbon-to-hydrogen bonds gain more s-character, which ...
Since three-membered rings are very strained (bond angles forced to be 60˚), sp 3 hybridization is more favorable than sp 2 hybridization. For the sp 3 hybridized hydrate the bonds have to be distorted by about 49˚, while for the sp 2 hybridized ketone the bond angle distortion is about 60˚.
Only bonding with 4 equivalent substituents results in exactly sp 3 hybridization. For molecules with different substituents, we can use isovalent hybridization to rationalize the differences in bond angles between different atoms. In the molecule methyl fluoride for example, the HCF bond angle (108.73°) is less than the HCH bond angle (110.2 ...