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The operator ~= is exactly the negation of equality (==). See docs. thanks a lot for pointing to the docs pushkin - for some reason googling ~= did not work for me. But now that I see the code, it makes a lot of sense.
In Lua's case, the language is intended to be an embedded scripting language, so any changes that make the language more complex or potentially make the compiler/runtime even slightly larger or slower may go against this objective.
Lua is deliberately lightweight so it does not have a ternary operator. There are a couple of ways to get past this including using the and-or idiom. But I think that is bad for multiple reasons. Mainly because beginners don't understand it though. I suggest using a function:
Basically dot syntax like object.method(object,args) retrieves object twice, while object:method(arg) retrieves object only once. If object is a global, upvalue or table field, then : is faster than .. . is never faster than :.
To anyone with the same sort of doubts about lua's syntax, i'd recommend checking the documentation here and keeping it handy. It'll be useful while learning. It'll be useful while learning. if-statement
If you are splitting a string in Lua, you should try the string.gmatch () or string.sub () methods. Use the string.sub () method if you know the index you wish to split the string at, or use the string.gmatch () if you will parse the string to find the location to split the string at. Example using string.gmatch () from Lua 5.1 Reference Manual:
Because control structures in Lua only consider nil and false to be false, and anything else to be true, this will always enter the if statement, which is not what you want either. There is no way that you can use binary operators like those provided in programming languages to compare a single variable to a list of values.
The lua-magic values must come after all those pre-processing steps, else precision-loss may occur. And finally, restore original sign of input. The 2 "multiplies" are simply low-overhead sign-flipping. sign-flips 4 times for originally negative values (2 manual flips and round-trip to end of mantissa), while any x >= 0 , including that of -0.0 ...
I have written a program to print a matrix after some computations and I am getting an output of nan for all elements. I want to break a for loop as soon as the matrix's first element becomes nan to
1. I'm in a situation where I have. if A and B and C then. X. end. Which if I understood it correctly, means it will only execute X if all three conditions (A,B,and C) are met. That's fine by itself, But, I need/want it to at the same time also check something that's like an "or if" statement, that is. if A and B and C [or if] A and D [or if] A ...