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  2. Project Euler - Wikipedia

    en.wikipedia.org/wiki/Project_Euler

    The first Project Euler problem is Multiples of 3 and 5. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. It is a 5% rated problem, indicating it is one of the easiest on the site.

  3. Grid method multiplication - Wikipedia

    en.wikipedia.org/wiki/Grid_method_multiplication

    so 3 × 17 = 30 + 21 = 51. This is the "grid" or "boxes" structure which gives the multiplication method its name. Faced with a slightly larger multiplication, such as 34 × 13, pupils may initially be encouraged to also break this into tens. So, expanding 34 as 10 + 10 + 10 + 4 and 13 as 10 + 3, the product 34 × 13 might be represented:

  4. Proportional reasoning - Wikipedia

    en.wikipedia.org/wiki/Proportional_reasoning

    So the answer is 3 because ⁠ 1 / 2 ⁠ × 3 × 8 = 12." A correct multiplicative answer is relatively rare. By far the most common answer is something like: "2 units because the water level on the right side increased by two units so the water level on the left side must decrease by two units and 4 – 2 = 2."

  5. Problem set - Wikipedia

    en.wikipedia.org/wiki/Problem_set

    [3] [4] They are usually issued once every week or two weeks, and due one or two weeks later. [ 4 ] [ 5 ] If used as part of a summative assessment they are usually given a low weight , [ 6 ] between 10% and 25% of the total mark of the course for all problem sets put together, [ 3 ] [ 5 ] and sometimes will count for nothing if the student ...

  6. 4 Pics 1 Word Cheats and Tips Guide - AOL

    www.aol.com/news/2013-02-12-whats-the-word...

    4 Pics 1 Word is a smash-hit mobile game and like all great games, the premise is wonderfully simple. ... Weekend Puzzle Solving (2/15) 13 More Answers. 13 More Answers (2/14) Cheats. Cheats (2/14 ...

  7. Singapore math - Wikipedia

    en.wikipedia.org/wiki/Singapore_math

    They would then solve the problem by inferring the shorter part to be 30. The bar model can be drawn as a comparison model to compare two bars of unequal lengths, which can then be used to solve a subtraction problem. The whole-part model can also be used to solve problems involving multiplication or division. [26]

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