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The range and the maximum height of the projectile do not depend upon its mass. Hence range and maximum height are equal for all bodies that are thrown with the same velocity and direction. The horizontal range d of the projectile is the horizontal distance it has traveled when it returns to its initial height (=).
To find the angle giving the maximum height for a given speed calculate the derivative of the maximum height = / with respect to , that is = / which is zero when = / =. So the maximum height H m a x = v 2 2 g {\displaystyle H_{\mathrm {max} }={v^{2} \over 2g}} is obtained when the projectile is fired straight up.
Full width at half maximum. In a distribution, full width at half maximum (FWHM) is the difference between the two values of the independent variable at which the dependent variable is equal to half of its maximum value. In other words, it is the width of a spectrum curve measured between those points on the y-axis which are half the maximum ...
The path of this projectile launched from a height y 0 has a range d.. In physics, a projectile launched with specific initial conditions will have a range.It may be more predictable assuming a flat Earth with a uniform gravity field, and no air resistance.
The physics of a bouncing ball concerns the physical behaviour of ... The equations imply that the maximum height (H) ... H is the maximum height of the ball, ...
Significant wave height H 1/3, or H s or H sig, as determined in the time domain, directly from the time series of the surface elevation, is defined as the average height of that one-third of the N measured waves having the greatest heights: [5] / = = where H m represents the individual wave heights, sorted into descending order of height as m increases from 1 to N.
The metacentric height (GM) is a measurement of the initial static stability of a floating body. [1] It is calculated as the distance between the centre of gravity of a ship and its metacentre . A larger metacentric height implies greater initial stability against overturning.
Consider a ball whose mass is m dropped from height h. The acceleration g of free fall is approximately constant, so the weight force of the ball mg is constant. The product of force and displacement gives the work done, which is equal to the gravitational potential energy, thus U g = m g h . {\displaystyle U_{g}=mgh.}