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The gravity g′ at depth d is given by g′ = g(1 − d/R) where g is acceleration due to gravity on the surface of the Earth, d is depth and R is the radius of the Earth. If the density decreased linearly with increasing radius from a density ρ 0 at the center to ρ 1 at the surface, then ρ(r) = ρ 0 − (ρ 0 − ρ 1) r / R, and the ...
G = 6.673 × 10 −11 Nm 2 /kg 2 is the gravitational constant, m = 5.975 × 10 24 kg is the mass of the earth, a = 6.378 × 10 6 m is the average radius of the earth, z is the geometric height in meters
The gravitational potential (V) at a location is the gravitational potential energy (U) at that location per unit mass: =, where m is the mass of the object. Potential energy is equal (in magnitude, but negative) to the work done by the gravitational field moving a body to its given position in space from infinity.
In addition to Poynting, measurements were made by C. V. Boys (1895) [25] and Carl Braun (1897), [26] with compatible results suggesting G = 6.66(1) × 10 −11 m 3 ⋅kg −1 ⋅s −2. The modern notation involving the constant G was introduced by Boys in 1894 [12] and becomes standard by the end of the 1890s, with values usually cited in the ...
However, to distinguish acceleration relative to free fall from simple acceleration (rate of change of velocity), the unit g is often used. One g is the force per unit mass due to gravity at the Earth's surface and is the standard gravity (symbol: g n), defined as 9.806 65 metres per second squared, [5] or equivalently 9.806 65 newtons of force ...
The metric captures all the geometric and causal structure of spacetime, being used to define notions such as time, distance, volume, curvature, angle, and separation of the future and the past. In general relativity, the metric tensor plays the role of the gravitational potential in the classical theory of gravitation, although the physical ...
For two pairwise interacting point particles, the gravitational potential energy is the work that an outside agent must do in order to quasi-statically bring the masses together (which is therefore, exactly opposite the work done by the gravitational field on the masses): = = where is the displacement vector of the mass, is gravitational force acting on it and denotes scalar product.
The gravity gradient (variation with height) above Earth's surface is about 3.1 μGal per centimeter of height (3.1 × 10 −6 s −2), resulting in a maximal difference of about 2 Gal (0.02 m/s 2) from the top of Mount Everest to sea level.