Search results
Results from the WOW.Com Content Network
Graph showing the difference between UT1 and UTC. Vertical segments correspond to leap seconds. In about AD 140, Ptolemy, the Alexandrian astronomer, sexagesimally subdivided both the mean solar day and the true solar day to at least six places after the sexagesimal point, and he used simple fractions of both the equinoctial hour and the seasonal hour, none of which resemble the modern second. [8]
The fraction of the day is found by converting the number of hours, minutes, and seconds after noon into the equivalent decimal fraction. Time intervals calculated from differences of Julian Dates specified in non-uniform time scales, such as UTC, may need to be corrected for changes in time scales (e.g. leap seconds). [8]
While TT is only theoretical, it is commonly realized as TAI + 32.184 seconds where TAI is UTC plus the current leap seconds, so ΔT = UTC − UT1 + (leap seconds) + 32.184 s. This can be rewritten as ΔT = (leap seconds) + 32.184 s − DUT1, where DUT1 is UT1 − UTC.
The Julian calendar ended up being 11 minutes and 14 seconds longer than the tropical year — the time it takes for seasons to repeat. In the late 16th century, Pope Gregory XIII improved the ...
An influential time scientist has suggested that Earth do away with leap seconds and go for a leap minute instead. A Time Scientist Watches the World's 2 Official Clocks. He Says We Need a 'Leap ...
1.67 minutes (or 1 minute 40 seconds) 10 3: kilosecond: 1 000: 16.7 minutes (or 16 minutes and 40 seconds) 10 6: megasecond: 1 000 000: 11.6 days (or 11 days, 13 hours, 46 minutes and 40 seconds) 10 9: gigasecond: 1 000 000 000: 31.7 years (or 31 years, 252 days, 1 hour, 46 minutes, 40 seconds, assuming that there are 7 leap years in the interval)
On a prograde planet like the Earth, the sidereal day is shorter than the solar day. At time 1, the Sun and a certain distant star are both overhead. At time 2, the planet has rotated 360° and the distant star is overhead again (1→2 = one sidereal day). But it is not until a little later, at time 3, that the Sun is overhead again (1→3 = one solar day). More simply, 1→2 is a complete ...
When dealing with periods that do not encompass a UTC leap second, the difference between two Unix time numbers is equal to the duration in seconds of the period between the corresponding points in time. This is a common computational technique. However, where leap seconds occur, such calculations give the wrong answer.