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Most 1-bromoalkanes are prepared by free-radical addition of hydrogen bromide to the 1-alkene, which is 1-pentene in the case of 1-bromopentane. These conditions lead to anti-Markovnikov addition, giving the 1-bromo derivative. [2] It is also formed by the reaction of 1-pentanol with hydrogen bromide.
H 2 C=CH 2 + HBr → H 3 C-CH 2 Br. Bromoethane is inexpensive and would rarely be prepared in the laboratory. A laboratory synthesis includes reacting ethanol with a mixture of hydrobromic and sulfuric acids. An alternate route involves refluxing ethanol with phosphorus and bromine; phosphorus tribromide is generated in situ. [4]
On the right, an empty pi-antibonding orbital on C 2 H 4 overlaps with a filled d-orbital on the metal. The Dewar–Chatt–Duncanson model is a model in organometallic chemistry that explains the chemical bonding in transition metal alkene complexes. The model is named after Michael J. S. Dewar, [1] Joseph Chatt and L. A. Duncanson. [2] [3]
2-Phenethyl bromide (C 6 H 5 CH 2 CH 2 Br) is produced via this route from styrene. Hydrogen bromide can also be used to convert alcohols to alkyl bromides. This reaction, that must be done under low temperature conditions, is employed in the industrial synthesis of allyl bromide: HOCH 2 CH=CH 2 + HBr → BrCH 2 CH=CH 2 + H 2 O
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An alkyne trimerisation is a [2+2+2] cycloaddition reaction in which three alkyne units (C≡C) react to form a benzene ring. The reaction requires a metal catalyst. The process is of historic interest as well as being applicable to organic synthesis. [1] Being a cycloaddition reaction, it has high atom economy.
The Prins reaction is an organic reaction consisting of an electrophilic addition of an aldehyde or ketone to an alkene or alkyne followed by capture of a nucleophile or elimination of an H + ion. [1] [2] [3] The outcome of the reaction depends on reaction conditions.
1,1,2,2-Tetrabromoethane, or simply tetrabromoethane (TBE), is a halogenated hydrocarbon, chemical formula C 2 H 2 Br 4.Although three bromine atoms may bind to one of the carbon atoms creating 1,1,1,2-tetrabromoethane this is not thermodynamically favorable, so in practice tetrabromoethane is equal to 1,1,2,2-tetrabromoethane, where each carbon atom binds two bromine atoms.