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  2. File:Parallelogram law squares.svg - Wikipedia

    en.wikipedia.org/wiki/File:Parallelogram_law...

    Due to the parallelogram law, the sum of areas of the blue squares equals the sum of areas of the red squares. Source: Own work: Author: Cmglee: Licensing.

  3. Geometric Shapes (Unicode block) - Wikipedia

    en.wikipedia.org/wiki/Geometric_Shapes_(Unicode...

    Geometric Shapes; Range: U+25A0..U+25FF (96 code points) Plane: BMP: Scripts: Common: Symbol sets: Control code graphics Geometric shapes: Assigned: 96 code points

  4. Missing square puzzle - Wikipedia

    en.wikipedia.org/wiki/Missing_square_puzzle

    Splitting the thin parallelogram area (yellow) into little parts, and building a single unit square with them. The key to the puzzle is the fact that neither of the 13×5 "triangles" is truly a triangle, nor would either truly be 13x5 if it were, because what appears to be the hypotenuse is bent.

  5. Parallelogram - Wikipedia

    en.wikipedia.org/wiki/Parallelogram

    The area of the parallelogram is the area of the blue region, which is the interior of the parallelogram. The base × height area formula can also be derived using the figure to the right. The area K of the parallelogram to the right (the blue area) is the total area of the rectangle less the area of the two orange triangles. The area of the ...

  6. Pattern Blocks - Wikipedia

    en.wikipedia.org/wiki/Pattern_blocks

    Christopher Danielson developed a new set of blocks, called Twenty-First Century Pattern Blocks. [8] The rhombus in this set has the same size as the blue rhombus in the traditional set. The dart and the 30°–60°–90° triangle have the same area, while the kite and the hexagon are twice that area. Like the traditional set, all the angles ...

  7. Parallelogram law - Wikipedia

    en.wikipedia.org/wiki/Parallelogram_law

    Vectors involved in the parallelogram law. In a normed space, the statement of the parallelogram law is an equation relating norms: ‖ ‖ + ‖ ‖ = ‖ + ‖ + ‖ ‖,.. The parallelogram law is equivalent to the seemingly weaker statement: ‖ ‖ + ‖ ‖ ‖ + ‖ + ‖ ‖, because the reverse inequality can be obtained from it by substituting (+) for , and () for , and then simplifying.

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