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From a permutations perspective, let the event A be the probability of finding a group of 23 people without any repeated birthdays. Where the event B is the probability of finding a group of 23 people with at least two people sharing same birthday, P(B) = 1 − P(A).
A naive application of the even-odd rule gives (,) = = () ()where P(m,n) is the probability of m people having all of n possible birthdays. At least for P(4,7) this formula gives the same answer as above, 525/1024 = 8400/16384, so I'm fairly confident it's right.
The birthday problem asks, for a set of n randomly chosen people, what is the probability that some pair of them will have the same birthday? The problem itself is mainly concerned with counterintuitive probabilities, but we can also tell by the pigeonhole principle that among 367 people, there is at least one pair of people who share the same ...
'We plan to make every birthday a real family event where birthdays get celebrated individually and together.' News & Star says the chances of having four birthdays on the same day is 133,225 to 1.
Each girl was born on the same day, exactly three years apart. That's right — Sophia, 9, Giuliana, 6, Mia, 3, and Valentina, 2.5 weeks old — have the exact same birthday.
Additionally, University of North Carolina hospitals reported 40 walking pneumonia cases in the last week of October compared to no cases the same time last year. Some hospitals seeing increase in ...
Usually, coincidences are chance events with underestimated probability. [3] An example is the birthday problem, which shows that the probability of two persons having the same birthday already exceeds 50% in a group of only 23 persons. [4] Generalizations of the birthday problem are a key tool used for mathematically modelling coincidences. [5]
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