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Molar concentration or molarity is most commonly expressed in units of moles of solute per litre of solution. [1] For use in broader applications, it is defined as amount of substance of solute per unit volume of solution, or per unit volume available to the species, represented by lowercase : [2]
It is equivalent to the units gram per millilitre (g/mL) and kilogram per litre (kg/L). The density of water is about 1 g/cm 3, since the gram was originally defined as the mass of one cubic centimetre of water at its maximum density at 4 °C (39 °F). [1]
In chemistry, the mass concentration ρ i (or γ i) is defined as the mass of a constituent m i divided by the volume of the mixture V. [1]= For a pure chemical the mass concentration equals its density (mass divided by volume); thus the mass concentration of a component in a mixture can be called the density of a component in a mixture.
One example of standard conditions for the calculation of SCCM is = 0 °C (273.15 K) [1] and = 1.01 bar (14.72 psia) and a unity compressibility factor = 1 (i.e., an ideal gas is used for the definition of SCCM). [2] This example is for the semi-conductor-manufacturing industry.
Conversions between units in the metric system are defined by their prefixes (for example, 1 kilogram = 1000 grams, 1 milligram = 0.001 grams) and are thus not listed in this article. Exceptions are made if the unit is commonly known by another name (for example, 1 micron = 10 −6 metre).
Volume to mass conversions for some common cooking ingredients; ingredient density g/mL [note 5] metric cup 250 mL imperial cup ≈284 mL U.S. customary cup ≈237 mL [note 6] g oz g oz g oz water [note 7] 1 [note 8] 249–250 8.8 283–284 10 236–237 8.3 [note 9] granulated sugar 0.8 [20] 200 7.0 230 8.0 190 6.7 wheat flour 0.5–0.6 [20 ...
In engineering and physics, g c is a unit conversion factor used to convert mass to force or vice versa. [1] It is defined as = In unit systems where force is a derived unit, like in SI units, g c is equal to 1.
V eq is the volume of titrant (ml) consumed by the crude oil sample and 1 ml of spiking solution at the equivalent point, b eq is the volume of titrant (ml) consumed by 1 ml of spiking solution at the equivalent point, 56.1 g/mol is the molecular weight of KOH, W oil is the mass of the sample in grams. The normality (N) of titrant is calculated as: