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— "Values ranging from 21.3 to 21.5 gm/cm 3 at 20 °C have been reported for the density of annealed platinum; the best value being about 21.45 gm/cm 3 at 20 °C." 21.46 g/cm 3 — Rose, T. Kirke. The Precious Metals, Comprising Gold, Silver and Platinum .
Upon freezing, the volume of mercury decreases by 3.59% and its density changes from 13.69 g/cm 3 when liquid to 14.184 g/cm 3 when solid. The coefficient of volume expansion is 181.59 × 10 −6 at 0 °C, 181.71 × 10 −6 at 20 °C and 182.50 × 10 −6 at 100 °C (per °C). Solid mercury is malleable and ductile, and can be cut with a knife.
The density 13 595.1 kg/m 3 chosen for this definition is the approximate density of mercury at 0 °C (32 °F), and 9.806 65 m/s 2 is standard gravity. The use of an actual column of mercury to measure pressure normally requires correction for the density of mercury at the actual temperature and the sometimes significant variation of gravity ...
Spectral lines of mercury: ... Density [kg/m3 at s.t.p.] Density [g/cm3 near room temperature] [g/cm3 ... density gpcm3nrt 3: density gpcm3nrt 3: no description. Unknown:
Hi. I'm trying to understand the answer to this question. Assuming that the given answer on that site is correct: I don't understand why ρ is replaced with the value 3.6 * 10^3. My understanding is that ρ is the density of mercury, so it should be around 1.35 * 10^4. At least, that's the value I get when I google "density of mercury in kg/m3".
This is the pressure resulting from a column of mercury of 760 mm in height at 0 °C. For the density of mercury, use ρ Hg = 13,595 kg/m 3 and for gravitational acceleration use g = 9.807 m/s 2. If water were used (instead of mercury) to meet the standard atmospheric pressure, a water column of roughly 10.3 m (33.8 ft) would be needed.
The kilogram per cubic metre (symbol: kg·m −3, or kg/m 3) is the unit of density in the International System of Units (SI). It is defined by dividing the SI unit of mass, the kilogram, by the SI unit of volume, the cubic metre. [1]
Thus the orbital period in low orbit depends only on the density of the central body, regardless of its size. So, for the Earth as the central body (or any other spherically symmetric body with the same mean density, about 5,515 kg/m 3, [2] e.g. Mercury with 5,427 kg/m 3 and Venus with 5,243 kg/m 3) we get: T = 1.41 hours