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Allows triple output units. See: full list. 1.0 short ton (0.91 t) ST t; ST MT; ST LT; short ton short ton stone: st st 14 lb used previously in the British Commonwealth except Canada. Allows triple output units. See: full list. 1.0 st (14 lb; 6.4 kg) st kg; st lb; pound: lb lb Allows triple output units. See: full list. 1.0 lb (0.45 kg) lb kg ...
The 35.1 pounds is the 'theoretical" weight of the package if it had a density of 166 in 3 /lb or 10.4 lb/ft 3: (18 × 18 × 18) = 3.375 ft 3 × 10.4 lb/ft 3 = 35.1 lb. Note that for the USPS there are two different calculations for DIM weight: (L × W × H)/194 for domestic shipments and (L × W × H)/166 for international shipments.
Conversions between units in the metric system are defined by their prefixes (for example, 1 kilogram = 1000 grams, 1 milligram = 0.001 grams) and are thus not listed in this article. Exceptions are made if the unit is commonly known by another name (for example, 1 micron = 10 −6 metre).
This improper name persists, especially in elementary textbooks. In biology, the unit "%" is sometimes (incorrectly) used to denote mass concentration, also called mass/volume percentage. A solution with 1 g of solute dissolved in a final volume of 100 mL of solution would be labeled as "1%" or "1% m/v" (mass/volume). This is incorrect because ...
A U.K. deal equaled 7 ft × 6 ft × 2 + 1 ⁄ 2 in, while a U.S. deal equaled 12 ft × 11 in × 1 + 1 ⁄ 2 in. [7] Demiard – an old French unit of volume. When France metricated, it survived in Louisiana and Quebec. The demiard eventually became associated with the American and British half-pint rather than French units. [7] Firlot; Hekat ...
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The volume of such a mixture is slightly less than the sum of the volumes of the components. Thus, by the above definition, the term "40% alcohol by volume" refers to a mixture of 40 volume units of ethanol with enough water to make a final volume of 100 units, rather than a mixture of 40 units of ethanol with 60 units of water.
The ideal gas equation can be rearranged to give an expression for the molar volume of an ideal gas: = = Hence, for a given temperature and pressure, the molar volume is the same for all ideal gases and is based on the gas constant: R = 8.314 462 618 153 24 m 3 ⋅Pa⋅K −1 ⋅mol −1, or about 8.205 736 608 095 96 × 10 −5 m 3 ⋅atm⋅K ...
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