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Overflow cannot occur when the sign of two addition operands are different (or the sign of two subtraction operands are the same). [1] When binary values are interpreted as unsigned numbers, the overflow flag is meaningless and normally ignored. One of the advantages of two's complement arithmetic is that the addition and subtraction operations ...
The result should be 510 which is the 9-bit value 111111110 in binary. The 8 least significant bits always stored in the register would be 11111110 binary (254 decimal) but since there is carry out of bit 7 (the eight bit), the carry is set, indicating that the result needs 9 bits. The valid 9-bit result is the concatenation of the carry flag ...
The register width of a processor determines the range of values that can be represented in its registers. Though the vast majority of computers can perform multiple-precision arithmetic on operands in memory, allowing numbers to be arbitrarily long and overflow to be avoided, the register width limits the sizes of numbers that can be operated on (e.g., added or subtracted) using a single ...
The formal definition of an arithmetic shift, from Federal Standard 1037C is that it is: . A shift, applied to the representation of a number in a fixed radix numeration system and in a fixed-point representation system, and in which only the characters representing the fixed-point part of the number are moved.
The advantage of skew binary is that each increment operation can be done with at most one carry operation. This exploits the fact that (+) + = +.Incrementing a skew binary number is done by setting the only two to a zero and incrementing the next digit from zero to one or one to two.
0x90 is the one-byte encoding for XCHG AX,AX in 16-bit code and XCHG EAX,EAX in 32-bit code. In long mode, XCHG RAX,RAX requires two bytes, as it would begin with an REX.W prefix, making the encoding 0x48 0x90. However, 0x90 is interpreted as a NOP in long mode regardless of whether it is preceded by 0x48. [2] multi-byte NOP
A bitwise AND is a binary operation that takes two equal-length binary representations and performs the logical AND operation on each pair of the corresponding bits. Thus, if both bits in the compared position are 1, the bit in the resulting binary representation is 1 (1 × 1 = 1); otherwise, the result is 0 (1 × 0 = 0 and 0 × 0 = 0).
To achieve this, the binary code can initially be loaded into contiguous bytes of the array for the simulator to "read", interpret and execute entirely within the memory containing the same array. If necessary, to completely avoid buffer overflow problems, bounds checking can usually be inserted by the compiler (or if not, hand coded in the ...