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The rings are interlocked so as not to become misplaced. A puzzle ring is a jewelry ring made up of multiple interconnected bands, which is a type of mechanical puzzle most likely developed as an elaboration of the European gimmal ring. [1] The puzzle ring is also sometimes called a "Turkish wedding ring" or "harem ring."
A baguenaudier Diagrammatic representation of a four-ring baguenaudier A metal version of the puzzle. Baguenaudier (pronounced; French for "time-waster"), [1] also known as the Chinese rings, Cardan's suspension, Cardano's rings, Devil's needle or five pillars puzzle, is a disentanglement puzzle featuring a loop which must be disentangled from a sequence of rings on interlinked pillars. [1]
Several subtypes are included under this category, the names of which are sometimes used synonymously for the group: wire puzzles; nail puzzles; ring-and-string puzzles; et al. [2] [3] Although the initial object is disentanglement, the reverse problem of reassembling the puzzle can be as hard as—or even harder than—disentanglement. There ...
Animation of a cut napkin ring with constant height In geometry , the napkin-ring problem involves finding the volume of a "band" of specified height around a sphere , i.e. the part that remains after a hole in the shape of a circular cylinder is drilled through the center of the sphere.
The ant on a rubber rope is a mathematical puzzle with a solution that appears counterintuitive or paradoxical. It is sometimes given as a worm, or inchworm, on a rubber or elastic band, but the principles of the puzzle remain the same. The details of the puzzle can vary, [1] [2] but a typical form is as follows:
The 27-cube snake cube puzzle laid flat (top) and packed into a 3×3×3 cube (bottom, exploded view) – cubelets with straight holes are outlined [1] The snake cube is a mechanical puzzle, a chain of 27 or 64 cubelets, connected by an elastic band running through them. The band runs straight through certain cubes, but bends 90° in others ...
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The puzzle can be generalised to n glasses instead of four. For two glasses it is trivially solved in one turn by inverting either glass. For three glasses there is a two-turn algorithm. For five or more glasses there is no algorithm that guarantees the bell will ring in a finite number of turns. [2]
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