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Complexes of type $\\ce{MA3B3}$ have two geometrical isomers, namely: fac-isomer mer-isomer If we look closely at the mer-isomer, it has a plane of symmetry, so it is optically inactive. But the fac-
4. Does there exist a chiral compound with zero optical activity? It seems possible that for some (chiral) arrangement of atoms, the optical activity of one section of the molecule could be exactly compensated by another section of the molecule, even if these two sections are not mirror images of each other. Although this is just a mathematical ...
Two Isomeric alkenes A and B having molecular formula, C 5 H 9 C l on adding H 2, A gives optically inactive compound while B gives a chiral compound. The two isomer are The two isomer are View Solution
Depending on the polarity of the functional group the amino acid can be rendered optically inactive or active. The simplest of all amino acids, Glycine which has H as a functional group lacks optical acitivity, as the saturated alpha carbon is unsubstituted. Others among the 20 amino acids have D or L stereoisomers.
A term for the achiral member (s) of a set of diastereoisomers which also includes one or more chiral members. 1,2-Dimethylcyclohexane possesses two diastereomers, one cis and one trans form. The trans form is chiral, but the cis form is achiral, as explained above. Therefore, the cis form satisfies the above definition and is considered a meso ...
An optically inactive mixture A (C6H10O4) (C6H10O4) can be resolved into enantiomers and has the given NMR spectra. a) Draw either enantiomer. Use wedge and dash bonds, including for any H atoms on a chirality center. b) Give the structure for an isomer of mixture A that has a melting point that is appreciably different from that of mixture A ...
Why is (-)-butan-2-ol is optically inactive? Solution. Verified by Toppr. Butan−2−ol has asymmetric carbon (chiral center) with four different groups attached to the central carbon. As racemic mixture cancel each other out optically, such solutions do not rotate the plane polarized light, so they are optically inactive. Was this answer helpful?
axes of symmetry are irrelevant in determining the optical activity of a molecule. We only have to consider center and plane of symmetry. That said, the given molecules have several chiral centers, which is a great sign that the molecule may be optically active. If you will try to find the plane of symmetry, you won't find any.
The most stable conformation of optically inactive butane-2,3-diol is: (A) (B) (C) (D) I chose C as the correct answer but, in the answer key it is given to be B. C is the stagg...
Reason Both geometrical isomers of the complex $$[M(NH_3)_4Cl_2]$$ possess axis of symmetry. Assertion The geometrical isomer of the complex $$[M(NH_3)_4Cl_2]$$ are optically inactive.