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In control theory, overshoot refers to an output exceeding its final, steady-state value. [2] For a step input, the percentage overshoot (PO) is the maximum value minus the step value divided by the step value. In the case of the unit step, the overshoot is just the maximum value of the step
In control theory, overshoot refers to an output exceeding its final, steady-state value. [13] For a step input, the percentage overshoot (PO) is the maximum value minus the step value divided by the step value. In the case of the unit step, the overshoot is just the maximum value of the step response minus one.
How overshoot may be controlled by appropriate parameter choices is discussed next. Using the equations above, the amount of overshoot can be found by differentiating the step response and finding its maximum value. The result for maximum step response S max is: [3]
Tay, Mareels and Moore (1998) defined settling time as "the time required for the response curve to reach and stay within a range of certain percentage (usually 5% or 2%) of the final value." [ 2 ] Mathematical detail
The Riemann–Siegel formula used for calculating the Riemann zeta function with imaginary part T uses a finite Dirichlet series with about N = T 1/2 terms, so when finding about N values of the Riemann zeta function it is sped up by a factor of about T 1/2.
Siegel derived it from the Riemann–Siegel integral formula, an expression for the zeta function involving contour integrals. It is often used to compute values of the Riemann–Siegel formula, sometimes in combination with the Odlyzko–Schönhage algorithm which speeds it up considerably.
According to Valley & Wallman (1948, pp. 77–78), this result is a consequence of the central limit theorem and was proved by Wallman (1950): [23] [24] however, a detailed analysis of the problem is presented by Petitt & McWhorter (1961, §4–9, pp. 107–115), [25] who also credit Elmore (1948) as the first one to prove the previous formula ...
The equation relates values of the Riemann zeta function at the points s and 1 − s, in particular relating even positive integers with odd negative integers. Owing to the zeros of the sine function, the functional equation implies that ζ ( s ) has a simple zero at each even negative integer s = −2 n , known as the trivial zeros of ζ ( s ) .